Finding the derivative of y = a ^ x is the derivation process of y = a ^ x * LNA

Finding the derivative of y = a ^ x is the derivation process of y = a ^ x * LNA

Basic premise: (e ^ x) '= e ^ x, derivative formula of compound function
y =a^x = e^(xlna)
Because (e ^ x) '= e ^ x
So y '= (xlna)' * e ^ (xlna) = LNA * (a ^ x) = a ^ x * LNA

What is the derivative of xlna? It should be LNA + X / A, but the answer is LNA why

Where LNA is used as a constant, we only need to derive X
（x*lna)'=lna*(x)'=lna*1=lna

The derivative of a ^ x is a ^ x * LNA. Why is the derivative of a ^ (- x) - A ^ (- x) * LNA? Why is there a negative sign in front of it

The result is: the product of the inner function and the outer function. The outer function is a ^ (- x) * LNA
The derivative of the inner layer (- x) is - 1, and the product is - A ^ (- x) * LNA
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