Given the square of X + the square of Y + 4x-8y + 20 = 0, find the square of x = the square of Y

Given the square of X + the square of Y + 4x-8y + 20 = 0, find the square of x = the square of Y

The original formula = (x + 2) ^ 2 + (y-4) ^ 2 = 0, the sum of two squares is 0, which means that the two numbers are all 0, then x = - 2, y = 4, x ^ 2 = 4, y ^ 2 = 16

Given x square + y square + 4x-8y + 20, then x=___ ,y=____ (x square + y Square) square - y square = x square + 6, then x square + y square=___

This is the result of 178; + Y-8 y + 4x-8y + 20 = x \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\it's not easy

2X ^ 2 + xy-y ^ 2-4x + 8y-6 factorization

Lou Zhu, you even wrote the wrong question. The original question should be: 2x ^ 2 + xy-y ^ 2-4x + 8y-16
Original formula = (x + y-4) (2x-y + 4)