Given the binary linear equation 2x + 3Y + 6 = 0, use the algebraic expression of X to express y, and regard y as the function of X, draw its image, and answer according to the image (1) When x = 6, the value of Y. (2) when y = - 4, the value of X. (3) when y = 0, find the value of X, which is the solution of the linear equation of one variable? -. get the image-

Given the binary linear equation 2x + 3Y + 6 = 0, use the algebraic expression of X to express y, and regard y as the function of X, draw its image, and answer according to the image (1) When x = 6, the value of Y. (2) when y = - 4, the value of X. (3) when y = 0, find the value of X, which is the solution of the linear equation of one variable? -. get the image-

（1）y = - 2x/3 -2
(2) When x = 6, y = - 6
(3) When y = - 4, x = 3
(4) When y = 0, x = - 3; is the solution of 2x + 6 = 0
The image is a straight line passing through (- 3, 0) and (0, - 2)

We solve the binary linear equations ax + 3Y + A + 3 = 0, x + (A-2) y + 2 = 0 about X and y, and discuss the solution

The second formula: x + (A-2) y + 2 = 0 = = > x = 2 - (A-2) y
Substituting into Formula 1: 2a-a (A-2) y + 3Y + A + 3 = 0
That is: Y (A-3) (a + 1) = 3 (a + 1)
Therefore, there are:
When a = - 1, there are infinitely many solutions: y = t, x = 2 + 3T
If a = 3, there is no solution
When A-1, A3, y = 3 / (A-3), x = 2-3 (A-2) / (A-3) = - A / (A-3)

If the function y = 2x-3, the coordinates of any point in the image must satisfy the quadratic equation

Let's satisfy the equation y = 2x-3. The function y = 2x-3 is just the image representation of this equation