1 / 3-2 / 7X = 6 / 7-x, x = how much?

1 / 3-2 / 7X = 6 / 7-x, x = how much?


1/3-2/7x=6/7-x
x-2/7x=6/7-1/3
5/7x=18/21-7/21
5/7x=11/21
x=11/21*7/5
x=11/15



X-6=276/7-6/7X X=?


Multiply by 7 at the same time
7x-42=276-6x
7x+6x=276+42
13x=318
The solution is x = 318 / 13



15x+2.6-7x=9 x-9=0.5x-2 16x-271=3(5-2x) 7x-1.2
15x+2.6-7x=9
x-9=0.5x-2
16x-271=3(5-2x)
7x-1.2+0.9=4x
4(x+3.5)=8x-2.8
16-0.8x+0.2x=2.8
It's all about solving equations


1、x=0.8



Relationship between bivariate linear equation and coefficient
Given that α and β are the two roots of equation x2 + 5x + 2, find the value of α 2 + 3 α - 2 β + 6


∵ α+β=-5 ,αβ=2,∴ α²+3α-2β+6= α²+5α+2-2(α+β)+4=0-2X(-5)+4=14



What are the following exponential functions?
A.y=9^x+1
B.y=-9^x
C.y=(-9)^x
D.y=9^x


D. Y = 9 ^ x is in the form of y = a ^ x, AB is compound function, and C image is discontinuous



If the sum of the coefficients and constants of a quadratic equation of two variables is 0, then the equation must have a root_____


It's a quadratic equation of one variable
Let ax + BX + C = 0
It is known that a + B + C = 0
Then C = - (a + b)
The formula for finding the root of quadratic equation of one variable x = [- B plus minus root sign (b-4ac)] / 2A
C = - (a + b) generation, then x = [- B addition and subtraction (2a + b)] / 2A
X = 1 or [- 2 (a + b)] / 2A
That is, there must be a root that is 1. (if 2A + b > 0)



Exponential function plus minus
How to reduce it?
Where is the addition and subtraction?
It's best to have an example


Add after
Y = 4 ^ x move 2 units up to y = 4 ^ x + 1



If the equation 4x-3ax + 2-A = 0 has only one solution, then a=
No,


4x-3ax+2-a=0
(4-3a)x=a-2
Because the equation about X has only one solution
So (4-3a) ≠ 0
That is, a ≠ 4 / 3 [there is a unique solution x = (A-2) / (4-3a)]



The problem of exponential function
Which is the greater of 0.6 power of 0.5 and 0.5 power of 0.6
Don't tell me what the rules are,


The above is the method of fractional exponential power in junior three
If you are in grade one of senior high school, because you have learned the properties of various functions, you can compare them according to the following [an intermediate number]



Given that the equation 3ax plus 8 equals 2x (a minus 1), under what circumstances are a and X both non positive integers


3ax+8=2x(a--1)
3ax+8=2ax--2x
ax=--2(x+4)
Because a and X are both non positive integers,
So -- 2 (x + 4) > = 0
x+4=0
Because a is not a positive number,
So a = 0,
So x = -- 4