X + 7x-4x = how much?

X + 7x-4x = how much?

x+7x-4x
=8X-4X
=4X

7x-3(x +40)+2(50-4x)=10-3(50-2x)

7x-3(x +40)+2(50-4x)=10-3(50-2x)
7x-3x-120+100-8x=100-150+6x
6x-7x+3x+8x=150-100+100-120
10x=30
x=30÷10
x=3

7X+5X=60 X=?

7X+5X=60
12x=60
Move to:
x=5

What is the remainder of the product of 1981 × 1982 × 1983 × 1998 divided by 17

1998 = 1981 + 17 Therefore, the remainder is 0. Or: 17 × 117 = 1989. The product of 1981 × 1982 × 1983 ×. × 1998 is a multiple of 1989, so the product of 1981 × 1982 × 1983 ×. × 1998 is also a multiple of 17

If the inequality x ^ 2 + 2ax-3

Let f (x) = x & # 178; + 2ax-3, then the inequality X & # 178; + 2ax-30, that is, a & # 178; + 3 > 0, holds (1)
f(-1/2)-11/4 （2）
f(3)

The remainder is a.22 b.4

Answer B, always except the last 4

Given the function f (x) = x2 + (A-3) x-3a & nbsp; (a is a constant) (1) if a = 5, solve the inequality f (x) > 0; (2) if a ∈ R, solve the inequality f (x) > 0

(1) When a = 5, (1-minute) f (x) = x2 + 2x-15 = (x + 5) (x-3) ∪ (3, + ∞); (4-minute) (2) when a ∈ R, the two solutions of F (x) = x2 + (A-3) x-3a = (x + A) (x-3) ∪ f (x) = (x + a) (x-3) = 0 are 3, - A & nbsp; & nbsp; (3 points) ① when 3 = - A is a = - 3, the solution set of the original inequality is: (- ∞, 3) ∪ (3, + ∞); ② when 3 ＞ - A is a ＞ - 3, the solution set of the original inequality is: (- ∞, - a) ∪ (3, + ∞); ③ when 3 ＜ - A is a ＜ - 3, the solution set of the original inequality is: (- ∞, 3) ∪ (- A, + ∞); (12 points)

The remainder of 22-26 is () a.4 b.22

Quotient 0 remainder 22

Given a ∈ R, the inequality about X is solved: the square of X - (a + 3) x + 3a

x²-(a+3)x+3a

The quotient of a number divided by 83 is 32, and the remainder is 23. What is the number?

32×83+23
=2656+23
=2679
The number is 2679