x^2+4x+2/x^2+4x+3-x^2+7x+5/x^2+7x+6

x^2+4x+2/x^2+4x+3-x^2+7x+5/x^2+7x+6

(x²+4x+2)/(x²+4x+3)-(x²+7x+5)/(x²+7x+6)
=(x²+4x+2)/(x+1)(x+3)-(x²+7x+5)/(x+1)(x+6)
=[(x+6)(x²+4x+2)-(x+3)(x²+7x+5)]/(x+1)(x+3)(x+6)
=[x³+4x²+2x+6x²+24x+12-(x³+7x²+5x+3x²+21x+15)]/(x+1)(x+3)(x+6)
=-3/(x+1)(x+3)(x+6)

How to write the inspection process of 7x + 4x = 12.1?

For example:
Take x = 12 / 11 to the left of the equation
It's 12
So the left is equal to the right
So x = 12 / 11 is the solution of the equation

2.7x-1.9x = 12.4x, etc

2.7X-1.9X=12.4
0.8x=12.4
x=12.4÷0.8
x=15.5

What is the remainder of 80 eights divided by seven

80*8/7=91+3
The remainder is three

Let - 1 be less than or equal to X and less than or equal to 1, f (x) = x ^ 2 + ax + 3, when 0

F (x) = x ^ 2 + ax + 3, the image is a parabola with an opening upward, and the axis of symmetry is x = - A / 2
Due to 0

How much is the remainder of 2002 111111111 divided by 7?

1 try! When 1 1 is divided by 7, the remainder is 12 ones, when 11 is divided by 7, the remainder is 43 ones, when 111 is divided by 7, the remainder is 64 ones, when 1111 is divided by 7, the remainder is 55 ones, when 11111 is divided by 7, the remainder is 26 ones, the remainder is 7 = 0, and the remainder is 7 = 1

If the line ax + by-3 = 0 and the circle x2 + Y2 + 4x-1 = 0 are tangent to the point P (- 1,2), then the value of AB is ()
A. -3B. -2C. 2D. 3

The equation of a circle is changed into a standard equation, which is: (x + 2) 2 + y2 = 5, so the center coordinate of the circle is (- 2, 0), the radius r = 5, ∵ the line is tangent to the circle, ∵ the distance from the center of the circle to the line d = | - 2A − 3 | A2 + B2 = r = 5, which is reduced to A2 + 5b2-12a-9 = 0 ①, and the coordinate of the tangent point P is substituted into the linear equation, which is: - A + 2b-3 = 0 ②

Write all numbers with the same quotient and remainder (not 0) as 8

9/8=1...1
18/8=2...2
27/8=3...3
36/8=4...4
45/8=5...5
63/8=7...7

Given f (x) = x ^ 2009 + ax ^ 3-B / X-8, f (- 2) = 10, find f (2)

First of all, analyze:
f(x)=x^2009+ax^3-b/x-8
f(-x)=-x^2009-ax^3+b/x-8
Because f (- 2) = 10
So x ^ 2009 + ax ^ 3-B / x = 10 + 8 = 18
So f (2) = - 18-8 = - 26

If a two digit number is divided by 5, the quotient and the remainder are equal. What is the divisor?

The remainder must be less than the divisor 5, which may be 1, 2, 3, 4
If the quotient and the remainder are both 1, then the divisor is 1 × 5 + 1 = 6
If both the quotient and the remainder are 2, then the divisor is 2 × 5 + 2 = 12
If both the quotient and the remainder are 3, then the divisor is 3 × 5 + 3 = 18
If both the quotient and the remainder are 4, then the divisor is 4 × 5 + 4 = 24
So, the divisor may be 12, 18, 24