The square of 5x-7x-6 Square of 15x + X-2 Square of 6x + 13x-5 4X squared - 8x + 3 Why?

The square of 5x-7x-6 Square of 15x + X-2 Square of 6x + 13x-5 4X squared - 8x + 3 Why?

The square of 5x - 7x-6 = (5x + 3) (X-2)
The square of 15x + X-2 = (3x-1) (5x + 2)
Square of 6x + 13x-5 = (3x-1) (2x + 5)
4X squared - 8x + 3 = (2x-1) (2x-3)

7x-2(x+4)=12

7x-2(x+4)=12
7x-2x-8=12
5x=12+8=20
x=4

X ^ 2 + (7-x) ^ 2-25 = 0 = x ^ 2-7x + 12 = 0 = (x-3) (x-4) = 0 = X1 = 3, how to simplify x ^ 2-7x + 12 = 0 in x2 = 4

First of all: you can't wait so continuously! This expression is wrong~
x^2+(7-x)^2-25=0 =x^2-7x+12=0 =(x-3)(x-4)=0 =x1=3,x2=4
x^2+(7-x)^2-25=0
x^2+49-14x+x^2-25=0
2x^2-14x+24=0
x^2-7x+12=0
……

If the function FX = ax ^ 2 / 3 defined on R satisfies f (- 2) > F1, then the minimum value of FX is

From F (- 2) > F (1), 4 / 3A > A / 3, so a > 0
If f '(x) = 2aX / 3, Let f' (x) = 0, then x = 0
In (- infinity, 0), f '(x)

7.1 divided by 3.5, the quotient 2, the remainder is (); when the divisor and divisor expand 100 times at the same time, the quotient is (), the remainder is ()
emergency

0.1 2 10

Given the function FX = 2x × lnx-1, find the minimum value of the function FX and the tangent equation of FX at point (1, F1)
Given the function FX = 2x × lnx-1, the process of finding the minimum value of the function FX and the tangent equation of FX at the point (1, F1) & # 128524;

1. F (x) = 2xlnx-1, f '(x) = 2 (LNX + 1), Let f' (x) = 0, then x = 1 / E,
F "(x) = 2 / x, F" (1 / E) = 2E > 0, so x = 1 / E is the minimum point, and the minimum value = f (1 / E) = (- 2 / E) - 1
2. F (1) = - 1, tangent point is (1, - 1), k = f '(1) = 2, tangent equation is y = 2 (x-1) - 1, that is y = 2x-3

I divide 3 by 7 on the tenth digit of the divisor, and then I divide 7 by the product of divisor and quotient, and the remainder is ()
78 divided by 3
First, I divide 3 by 7 on the tenth digit of the divisor, and then I divide 7 by the product of divisor and quotient (the remainder is (); I combine the remainder and () on the individual digit into (divide 3 by () on the individual digit ()

X 2 6 1 8 18 6

Let f (x) = | x-a | + 2x, where a > 0. (I) when a = 2, find the solution set of the inequality f (x) ≥ 2x + 1; (II) if x ∈ (- 2, + ∞), f (x) > 0, find the value range of A

(I) when a = 2, the inequality f (x) ≥ 2x + 1, that is | X-2 | 1, | X-2 | 1, or X-2 ≤ - 1. The solution is x ≤ 1, or X ≥ 3, so the solution set of the inequality is {x | x ≤ 1, or X ≥ 3}. (II) ∵ f (x) = 3x − a, & nbsp; & nbsp; X ≥ ax + A, & nbsp; x < A, a > 0

The quotient of 43 divided by 7 is 6, and the remainder is 1. If the divisor and divisor are expanded 100 times, then the quotient is - and the remainder is——
3Q

The quotient of 43 divided by 7 is 6 and the remainder is 1. If the divisor and divisor are expanded 100 times, then the quotient is 6 and the remainder is 100

Given the function FX = | 2x-1 | + | 2x + a |, when a = - 4, find the solution set of the inequality FX > x + 3