Write out two polynomials which only contain the letters X and y, and satisfy the following conditions: 1. It is a six degree trinomial expression; 2. The coefficient of each term; 3. It does not contain a constant term; y. each term must contain X

Write out two polynomials which only contain the letters X and y, and satisfy the following conditions: 1. It is a six degree trinomial expression; 2. The coefficient of each term; 3. It does not contain a constant term; y. each term must contain X

3x^2y^2+3X^4Y^4
PS don't know if it's right or not. I'd better not copy me because I don't think it's correct (-_ -.sorry!）

Given that n is a positive integer, let n! = 1 * 2 * 3 *. * n, let m = 1! * 1 + 2! * 2 +. + 2007! * 2007, then what is the remainder of the integer divided by 2008?

m = 1!*1 + 2!*2 + 3!*3 + …… + 2007!*2007= (1!*1+ 1!*1)+ 2!*2 + 3!*3 + …… + 2007!*2007 - 1!*1= (2!*1 + 2!*2) + 3!*3 + …… + 2007!*2007 - 1= (3!*1 + + 3!*3) + …… + 2007!*2007 - 1…… =2008! - 1 case 2

How many jin of water is a liter of water?

One liter of water is equal to two Jin of water

1 divided by (2 divided by 3) divided by (3 divided by 4) divided by. (2007 divided by 2008)

1004
=1X3/2X4/3X.X2008/2007
Basically, the numerator and denominator can be deleted, leaving 2008 / 2

How many liters of water is one ton of water?

1 ton of water = 1000 kg = 1 cubic meter = 1000 cubic decimeter = 1000 liters
Note: 1 liter = 1 cubic decimeter

(2-1 divided by 2) multiplied by (2-2 divided by 3) multiplied by (2-3 divided by 4) multiplied by... Multiplied by (2-2007 divided by 2008)

The original formula of 2009 / 2 is (1 + 1 / 2) (1 + 1 / 3)... (1 + 1 / 2008) = 3 / 2 * 4 / 3 * 5 / 4... * 2009 / 2008 = 2009 / 2

How much water is a liter equal to?
I discussed with my colleagues for a long time, but I didn't come out. How much is a liter of gasoline?

One liter of water = 1 kg = 2 jin of water (the density of water is 1)
One liter gasoline = 0.75 kg = 1.5 kg (gasoline density 0.75)

What is the remainder of 1 divided by 7 in 2008

5. Divide 11111111 by 7 to get 1587301, and the number is in 158730 cycle. 2008-1 = 20072007 divided by 6 = 334, and the remaining number is 5

How many jin is a liter of water

Two Jin

What is the remainder of 2 ^ 2013 + 2011 ^ 2 divided by 7?

2^2013=8^671=(1+7)^671
So the remainder of 2 ^ 2013 divided by 7 is 1
2011^2=（287×7+2)^2
The remainder of 2011 ^ 2 divided by 7 is 4
1+4=5
So the remainder of 2 ^ 2013 + 2011 ^ 2 divided by 7 is 5