How many times are the following polynomials and their terms, their coefficients and degrees - x3y2-xy? + 2x-y-2

How many times are the following polynomials and their terms, their coefficients and degrees - x3y2-xy? + 2x-y-2

The quintic pentanomial formula, its coefficient and times are as follows: - x3y2, coefficient is - 1, times is 5-xy?, coefficient is - 1, times is 52X, coefficient is 2, times is 1-y, coefficient is - 1, times is 1-2, coefficient is - 2, times is 0

Extracting coefficients of polynomial power with MATLAB
For example, f = 3 * x ^ 5 + 2 * x ^ 2
Want to extract the coefficient [3,0,0,2,0,0]
Can it be realized

syms x
f=3*x^5 + 2*x^2;
A=sym2poly(f)
In this way?

Matlab polynomial calculation
For example, (6x ^ 3 + 4x ^ 2-5) / (12x ^ 3-7x ^ 2 + 3x + 9) when x = 2, the equation is = 0.7108

x = 2;
y = (6*x^3+4*x^2-5)/(12*x^3-7*x^2+3*x+9);

It is known that X1 + x2 = a, X1 * x2 = B. If a and B are used to represent the absolute value x1-x2, then the absolute value x1-x2 is equal to ()

Absolute value x1-x2 = under root sign (x1-x2) ^ 2 = under root sign {(x1 + x2) ^ 2-4x1 * x2} = under root sign (a ^ 2-4b)

X * 2-mx-1 = 0 two x1, X2, if the absolute value of x1-x2 is equal to 3, find M

Formula X1 = (M + (m ^ 2 + 4) ^ (1 / 2)) / 2
x2=-(m+(m^2+4)^(1/2))/2
x1-x2=(m^2+4)^(1/2)=3
M = 5 ^ (1 / 2) or
-5^(1/2)

A problem of absolute value inequality in Mathematics
|2x+5|-|x-4|

Classified discussion
1.x

The solution set of inequality ix-1i > 0 is_
The solution set of inequality IXI < 3 is__
The solution set of inequality IXI ＞ 6 is__
The solution set of inequality ix-1i ＞ 5 is__
The solution set of inequality ix-10i ≥ 0 is__ (these questions are for filling in the blanks. Write them in the way of containing intervals.)
The result of solving inequality i2x + 3I ＞ 5 is x ＜ - 4 and X ＞ 1
It's better to write down why I do this! I can do it, but I'm not sure if it's right!

(-∞,1)∪(1,+∞)
(-3,3)
(-∞,-6)∪(6,+∞)
(-∞,-4)∪(6,+∞)
(-∞,+∞)
That's right. Just write boldly

Let f (x) = | 2x + 1 | - | x-4 | (I) draw the graph of function y = f (x). (II) find the minimum value of function y = f (x)

(1) The function f (x) = | 2x + 1 | - | x-4 | = − x − 5, X ＜− 123x − 3, − 12 ≤ x ≤ 4x + 5, X ＞ 4 is simplified by using the zero segmentation method. The image of the function is shown in the figure. (II) according to the image, when x = - 12, the minimum value of function y = f (x) is - 412

How to calculate mathematical inequality with absolute value

First, determine whether the sum value in the absolute value sign is a positive number, 0, or a negative number
If it is a non negative number, the absolute value sign can be removed directly;
If it is negative, the absolute value sign is removed and a negative sign is added before the original value
For example:
If x ≥ 0, then | x + 2 | = x + 2
Known x

1. Known inequality | x-m|

1.|x-m|