Fill in the numbers according to the rules: half, quarter, eighth, () one, 128 one. The numbers in this column are getting closer and closer to ()

Fill in the numbers according to the rules: half, quarter, eighth, () one, 128 one. The numbers in this column are getting closer and closer to ()

One sixteenth, one thirty-two, one sixty-four is close to zero

Fill in half, three and half, seven, ten and twenty according to the rule

Twenty (23), (46)
1 / 2 + 3 = three and a half
Three and a half times 2 = 7
7+3=10
10*2=20
(add 3 and multiply by 2 in turn)

One half, three and one half, seven, ten, twenty, () () find the rules and continue to fill in

23 46
1.. 3 1 / 2 more than 1 / 2 3 10 more than 7 3 so the first bracket Wei 23-20 = 3 so it's 23
2. 7 divided by 3 and 1 / 2 = 2 20 / 10 = 2, so 46 / 23 = 2 gets 46

Fill in the numbers regularly, one sixth, one third, one half, fill in the numbers, five sixths, fill in the numbers

Two thirds, one

Fill in the numbers according to the rules: 1, 1, 3, half, 5, quarter, (), ()

Seven and one sixth, respectively

(x + 1 / 2) minus 1 / 4 = 2 / 3 solution

(x+1/2)-1/4=2/3
x+1/2-1/4-2/3=0
x+6/12-3/12-8/12=0
x-5/12=0
x=5/12

A lot of solutions! 1.1 - half x (two-thirds x + Half) = quarter
2. 17 and 5 / 6 x - (X-5 / 6) × 6 = 16 and 5 / 6
3.（2x－3）÷7＋5＝8
4.[(5＋x)]×10－10]÷10＝9

1.1-half x (two-thirds x + one-half) = quarter 4-2x (2x / 3 + 1 / 2) = 112-6x (2x / 3 + 1 / 2) = 312-4x ^ 2-3x = 34x ^ 2 + 3x-9 = 0x = - 3 + √ (3 ^ 2 + 4 * 4 * 9) / 2 * 4 = - 3 + 3 √ 17 / 8 or x = - 3 - √ (3 ^ 2 + 4 * 4 * 9) / 2 * 4 = - 3-3 √ 17 / 82

Solution equation: 2x + 3 / 2 = 28 1 / 2 x + 1 / 4 x = 24 x-0.6x = 24 x △ 4 / 3 = 8 / 9

2x+3/2=28
2x=53/2
x=53/4
x/2+x/4=24
3x/4=24
x=24×4/3=32
x-0.6x=24
0.4x=24
x=24/0.4=60
x÷(4/3)=8/9
x=(8/9)×(4/3)=32/27

x+[2−12(x−4)]＝2x+3．

Remove the bracket to get: x + 2-12x + 2 = 2x + 3, move the term to get: x-12x-2x = 3-2-2, merge the similar term to get: - 32x = - 1, change the coefficient of X to 1 to get: x = - 23

Given | x + 2 | + | Y-3 | = 0, find the value of negative 1 / 2 x-3 y + 4xy
If a and B are opposite to each other, CD is reciprocal to each other. The absolute value of M is 1. Find the value of (a + b) cd-2009m. There will be 1000 points

|x＋2|＋|y-3|=0
But | x + 2 | ≥ 0 | Y-3 | ≥ 0
So | x + 2 | = 0 and | Y-3 | = 0
x=-2 y=3
Negative half x-five-thirds y + 4xy
=-0.5*(-2)-5/3*3+4*(-2)*3
=1-5-24
=-28