12 calculate (1) the square of three thirds of X - (- the square of one-half of x) + (- the square of 2x) (2) (- the square of 9x - 3 + 2x)+（

12 calculate (1) the square of three thirds of X - (- the square of one-half of x) + (- the square of 2x) (2) (- the square of 9x - 3 + 2x)+（

(1) 3 / 2 x squared - (- 1 / 2 x squared) + - 2x squared
=3/2x^2+1/2x^2-2x^2
=0
The second question is not complete, please add

12 calculate (3) (a + B-C) + (B + C-A) + (c + a-b) (4) 2 (square of x-3x + 1) - 3 (square of 2x-x-2)

(1):（a+b-c）+（b+c-a）+（c+a-b）
=a+b-c+b+c-a+c+a-b
=a+b+c
(2) : 2 (square of x-3x + 1) - 3 (square of 2x-x-2)
=2x-6x square + 2-6x square + 3x + 6
=5x-12x square + 8

The square of (X -- 2) = the square of (2x + 3)

First expand, then shift and merge, and finally become a quadratic equation
(x - 2)² = (2x + 3)²
x² - 4x + 4 = 4x² + 12x + 9
3x² + 16x + 5 = 0
(3x+1)(x+5) = 0
So x = - 5 or x = - (1 / 3)

How to calculate the square of X + 2x = 2?
How to use and match

x²+2x=2
x²+2x+1=3
(x+1)²=3
x+1=±√3
x=-1±√3
x1=-1+√3,x2=-1-√3

Calculate the square of (X-2) - 2 (x + 1) (x-1) - x (2x-1)

Solution
(x-2)²-2(x+1)(x-1)-x(2x-1)
=x²-4x+4-2(x²-1)-2x²+x
=x²-4x+4-2x²+2-2x²+x
=(x²-2x²-2x²)+(-4x+x)+6
=-3x²-3x+6

The square of Y - 6xy = 4x, then y =?

∵y^2-6xy=4x ==>(y-3x)^2=9x^2+4x
==>y-3x=±√(9x^2+4x)
∴y=3x±√(9x^2+4x).

How to do the square of 13X - 6xy + Y - 4x + 1
Wrong, it's 13X squared - 6xy + y squared - 4x + 1 = 0, find the value of (xy-x squared) to the fifth power

9x2-6xy+y2+4x2-4x+1=0
(3x-y)2+(2x-1)2=0
2x-1=0
3x-y=0
X=0.5
Y=1.5

What method is still used for the square of 4xy-4x to the third power of Y-Y

The square of 4xy-the square of 4x to the third power of Y-Y
=-y(4x²-4xy+y²)
=-y(2x-y)²

The second power of 4x -- the square of 4xy + 4x-2y + y

The second power of 4x -- the square of 4xy + 4x-2y + y
=4x²-4xy+y²+2(2x-y)
=(2x-y)²+2(2x-y)
=(2x-y)(2x-y+2)

The fraction of 4xy-4x-y-y cubic factor

The fraction of 4xy-4x-y-y cubic factor
Extract the common factor y to get y (4xy-4x ^ 2-y ^ 2) = - Y (- 4xy + 4x ^ 2 + y ^ 2) = - Y (2x-y) ^ 2
Hello, I'm glad to answer your questions
If you don't understand this question, you can ask. If you are satisfied, remember to adopt it
If you have any other questions, please take this question and send it to me. Please understand
I wish you progress in your study
If you can, please click "adopt as a satisfactory answer" on this page