Given x + 2 + Y-3 = 0, find the value of negative two and half x-one and two-thirds y + 4xy

Given x + 2 + Y-3 = 0, find the value of negative two and half x-one and two-thirds y + 4xy

The absolute value is nonnegative, so x = - 2, y = 3
5-5 + 4 * (- 2) * 3 = - 24

If the line 2ay-1 = 0 is parallel to the line (3a-1) x + Y-1 = 0, then the real number a is equal to ()
A. 12B. -12C. 13D. -13

Because the two lines are parallel, their slopes are equal, that is, 3a-1 = 0, that is, a = 13

Let a and B be two nonparallel vectors, and X (3a-b) + y (2a-b) = 7a-3b, find the values of X and Y (A and B are vectors)

3x + 2Y = 7, - X-Y = - 3, simultaneous solution of the equations

Given: a = 5, find the value of 1-2a + A & sup2; under a + radical
A and B use their own methods to calculate and get the following different answers
The answer of a is: 1-2a + A & sup2; = 1-A & sup2; = a + 1-A = 1
The answer of B is: 1-2a + A & sup2 under a + radical; = a + A-1 = 2a-1 = 2 * 5-1 = 9
Which answer is wrong? Where is wrong? Why?

a=5
A + radical (1-2a + A ^ 2) = a + radical (A-1) ^ 2 = a + A-1 = 2a-1 = 2 * 5-1 = 9
A error, where the square root of the negative number is obtained after the square of the negative number is re squared [(1-A) < 0]

A quadratic problem with one variable for solving the equation of the first three solutions
Because 2x & sup2; ≥ 0, 2x & sup2; + 1 has a minimum value of 1, 2x & sup2; + 1 ≥ 1. Only when x = 0, can we get the minimum value of 1. Similarly, because - 2x & sup2; ≤ 0, so - 2x & sup2; + 1 has a maximum value of 1, that is - 2x & sup2; + 1 ≤ 1. Only when x = 0, can we get the maximum value of 1
(1) One side of the rectangular garden is against the wall, and the other three sides are fenced
1. If the total length of the fence is 12M, when the length x of the two sides of the garden adjacent to the wall is what, the area y of the garden is the largest? What is the maximum area?
2. If the total length of the fence is a m, what is the side length x, and what is the maximum area of the garden?

1. Y = x (12-2x) = - 2 (X & sup2; - 6x) = - 2 (X & sup2; - 6x + 9) + 18 = - 2 (x-3) & sup2; + 18 ≥ 18 ℅ if and only if x = 3, the equal sign holds. A: when the length of the two sides of the garden adjacent to the wall is 3M, the area of the garden is the largest, and the largest area is 18 m2. 2. Y = x (a-2x) = - 2 (X & sup2; + 0.5ax) = - 2 (X & S

Solve equation application problem
The population of a rural area is about 500000. In 2002, the number of people who didn't get well-off was 500000 times (1% - 68) = 160000
Assuming that the county plans to reduce the 160000 rural population who have not reached the well-off level to 102400 by the end of 2004 on the basis of 2002, what is the average annual reduction rate?

2002 to 2004 is two years
Suppose the average annual reduction of X
In 2003, it was 16 * (1-x)
In 2004, it was 16 * (1-x) * (1-x)
So 16 * (1-x) & sup2; = 10.24
(1-x)²=0.64
Obviously 1-x > 0
1-x=0.8
x=0.2=20%
So it's down 20% a year

The second order solution equation of the first three variables
200 fruit trees are planted in an orchard this year. Now it is planned to expand the planting area, so that the planting rate in the next two years will increase by the same percentage as that in the previous year, so that the total planting weight in three years (including this year) will be 1400?

Let this number be X,
Then 200 + 200 (1 + x) + 200 (1 + x) square = 1400
Then 200X square + 600x-800 = 0
The solution is x = 1 or - 4 (rounding off)
Then the percentage is 100%
A: the percentage is 100%

Calculation problem: square of (a + B + C) - (a + b) - (B + C)
A few more
The fourth power of X + 2x & # 179; + 2x & # 178; + 2x + 1
The 9th power of X + the 6th power of X + the 3rd power of X - 3
3x³-8x²-9

(a+b+c)²-(a+b)²-(b+c)²
=(a+b)²+c²+2(a+b)c-(a+b)²-(b²+c²+2bc）
=c²+2ac+2bc-b²-c²-2bc
=2ac-b²
x^9+x^6+x^3 -3
=(x^9-x^6)+(2x^6+x^3 -3)
=x^6(x^3-1)+(x^3-1)(2x^3+3)
=(x^3-1)(x^6+2x^3+3)
=(x-1)(x²+x+1)(x^6+2x^3+3)
x^4+2x³+2x²+2x+1
=x^4+2x³+x²+x²+2x+1
=x²(x²+2x+1)+(x²+2x+1)
=(x²+1)(x²+2x+1)
=(x²+1)(x+1)²
3x³-8x²-9
=3x³-9x²+x²-9
=3x²(x-3)+(x+3)(x-3)
=(3x²+x+3)(x-3)

Given 1 divided by 4 (x ^ 2Y ^ 3) ^ m multiplied by (2XY ^ N-10 ^ 2 = x ^ 4Y, find the value of (m ^ 2n) ^ 3
1 divided by 4 = one quarter

I want to ask the formula, (x ^ 2Y ^ 3) ^ m times (2XY ^ N-10 ^ 2 = x ^ 4Y). Where is the other right bracket?

If (X-Y) / (x + y) = 3, then (x + 2Y) / (6x-7y) is equal to

If (X-Y) / (x + y) = 3
Then X-Y = 3 (x + y)
x-y=3x+3y
So x = - 2Y
So (x + 2Y) / (6x-7y) = (- 2Y + 2Y) / (6 * (- 2Y) - 7Y) = 0
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