The solution of 2x + 3 (10-3x) = 25?

The solution of 2x + 3 (10-3x) = 25?


To get rid of the brackets, you have to
2x+30-9x=25
Transfer, get
2x-9x=25-30
That is - 7x = - 5
The solution is x = 5 / 7



The solution equation is: 1.2x-5 = 2.2. - 2 of a + 3 = 5.3.. 2-2 of 3x-1 = 2 of 7 + 3 of x-14.4.. - 2 {3-2x} = 12


1、2x-5=2
2x=2+5
2x=7
x=7/2
2、-a/2+3=5
-a+6=10
-a=10-6
-a=4
a=-4
3、2-3x/2=7/2+x/3-14
12-9x=21+2x-84
9x+2x=12-21+84
11x=75
x=75/11
4、-2(3-2x)=12
3-2x=-6
2x=3+6
2x=9
x=9/2



Decomposition factor: (1) 18x ^ 3-27x ^ 4-3x ^ 2 (2) x ^ 4-18x ^ 3 + 81 16A ^ 2B ^ 4-8ab ^ 2C ^ 2 + C ^ 4 (4) 9 (2x-y) ^ 2-6 (2x-y) + 1
Decomposition factor: (1) 18x ^ 3-27x ^ 4-3x ^ 2 (2) x ^ 4-18x ^ 3 + 81
(3)16a^2b^4-8ab^2c^2+c^4 (4)9(2x-y)^2-6(2x-y)+1


18x^3-27x^4-3x^2=-3x^2(-6x+9x^2+1)=-3x^2(9x^2-6x+1)=-3x^2(3x-1)^2x^4-18x^2+81=(x^2)^2-2*x^2*9+9^2=(x^2-9)^2=(x+3)^2(x-3)^216a^2b^4-8ab^2c^2+c^4=(4ab^2)^2-2*(4ab^2)*c^2+(c^2)^2=(4ab^2-c^2)^29(2x-y)^2-6...



x^4-2x^3-27x^2-44x+7
I want a specific process, that is, from the original formula to the following formula
(x^2+ax+1)(x^2+bx+7)
(x^2+ax-1)(x^2+bx-7)
(x+7)(x^3+x^2+bx+1)
(x-7)(x^3+x^2+bx-1)


x⁴-2x³-27x²-44x+7
You mean to use the undetermined coefficient method?
To use the undetermined coefficient method is to
Let the original formula = (X & sup2; + ax + 1) (X & sup2; + BX + 7) or = (X & sup2; + AX-1) (X & sup2; + bx-7)
[because the first term can be decomposed into X & # 8308; = x & sup2; * X & sup2; the last term can be decomposed into 7 = 1 * 7 or (- 1) * - 7]
Then open the brackets and merge the similar items
x⁴+(a+b)x³+(ab+8)x²+(7a+b)x+7=x⁴-2x³-27x²-44x+7
Or X & # 8308; + (a + b) x & sup3; + (AB-8) x & sup2; - (7a + b) x + 7 = x & # 8308; - 2x & sup3; - 27x & sup2; - 44x + 7
The two sides of the coefficient can be compared
a+b=-2
ab+8=-27
7a+b=-44
Or a + B = - 2
ab-8=-27
-7a-b=-44
By solving these two equations, we can get the following results
A = - 7, B = 5 [the second system of equations has no solution]
So the original formula = (X & sup2; - 7x + 1) (X & sup2; + 5x + 7)



To solve the equations 2Y - (x + 1) = 18 6 (2x-y) = 18 x + y


2y-(x+1)=18
2y-x=19
6(2x-y)=18x+y
12x-6y=18x+y
6x=-7y
X = - 7Y / 6
2y+7y/6=19
y=6
x=-7



(1.2x-x)*1.5=18×2


(1.2x-x)*1.5=18×2
1.2x-x=18*2÷1.5
0.2x=24
x=120



2X+(6-X]*2.6=18
Remember the format


3.2x + (6-x)* 2.6= 18
Remove brackets: 3.2X + 6 * 2.6-2.6x = 18
Transfer: 3.2x-2.6x = 18-6 * 2.6
6 x = 2.4
When the coefficient is changed to 1, x = 4



3 / 4x (84-x) = 1 / 2x + 18


347366



Find the value of (2x & # 178; - 18) / (4-4x + X & # 178;) / (x + 3) · (X-2) / (3-x)


(2x²-18)÷(4-4x+x²)÷(x+3)·(x-2)÷(3-x)
=2(x²-9)÷[(x+2)(x-2)]÷(x+3)*(x-2)÷(3-x)
=2[ (x-3) (x+3)]÷[(x+2)(x-2)]÷(x+3)*(x-2)÷(3-x)
=2(x-3)÷[(x+2)(x-2)]*(x-2)÷(3-x)
=-2÷[(x+2)(x-2)]*(x-2)
=-2÷(x+2)



What is the simplest common denominator of 2X-4, x ^ 2 + X-6, 3x ^ 2-12


2*(x-2)
(x-2)*(x+3)
3*(x-2)*(x+2)
So it's (X-2)