Find the inequality X / 2 + X / 6 + X / 12 + X / 20 +... + X / (n-1) n > n-1 There are no conditions. That's what I want you to ask! What should I do? There's another one. It's all from the teacher Comparing the difference between (A's Square minus B's Square plus 2) and (A's Square minus 2 times B's Square plus 1) is a little dizzy, Urgent! Thank you!

Find the inequality X / 2 + X / 6 + X / 12 + X / 20 +... + X / (n-1) n > n-1 There are no conditions. That's what I want you to ask! What should I do? There's another one. It's all from the teacher Comparing the difference between (A's Square minus B's Square plus 2) and (A's Square minus 2 times B's Square plus 1) is a little dizzy, Urgent! Thank you!

Inequality 12 / x-3 < 3 / 2x-5 3 (2x + 5) > 2 (4x + 3)
（1）2/X-3＜3/2X-5 （2） 3（2X+5）＞2（4X+3）

（1）
2/X-3/2X＜-2
1 / 2x-1 / 4, i.e. - 1 / 4

The set of inequalities {2x-10} is

{2x-10, i.e. 1 ＞ X / 2, X ＜ 2
The solution set is x < 2

Solving inequality (2x + 1) (x-3) - (2x + 3) (x-1) > = 12

(2x+1)(x-3)-(2x+3)(x-1)>=12
2x^2-5x-3-(2x^2+x-3)>=12
-6x>=12x
x

Given that the solution set of inequality 3x-1 / 2 > A + 2x / 4 is x > - 2, find the solution of inequality 1 / 3 (A-X) > 12 + a

-6-1/2=a-1
∴a=-11/2
∵1/3(a-x)>12+a
∴1/3(-11/2-x)>12-11/2
-11-2x>39
∴x

x+（x+1）/3

x+x+1/3

When a is a value, the solution set of inequality 3 (1-ax) > X-12 is X

Solution 3 (1-ax) > X-12
（3a+1)x＜15
The solution set is x < 6
∴15/(3a+1)=6
a=1/2
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(1) 3 is the solution of the inequality x + 3 > 5; 2) x is the solution of the inequality x + 3 > 5

D
① 3 + 3 > 5, correct
② X7-4 = 3 correct

-The solution set of 2x ≤ 6 is the system of inequalities x > - 2 and X

-The solution set of 2x ≤ 6 is (x > = - 3),
Inequalities x > - 2 and X

On the inequality system of X, (x + 9) / 2 > x-3,2 (x + 1) / 3

(x+9)/2>x-3
x+9>2x-6
-x>-15
x