If there are only four integer solutions to the inequality system of X, then the value range of a is () The system of inequalities is x-a≥0 5-2x＞1 Why? Because there are only four integer solutions - 1, - 2 So a should be between - 3 and - 2?

If there are only four integer solutions to the inequality system of X, then the value range of a is () The system of inequalities is x-a≥0 5-2x＞1 Why? Because there are only four integer solutions - 1, - 2 So a should be between - 3 and - 2?

X-a ≥ 05-2x ＞ 1 is simplified to X ≥ ax ＜ 2, because there are only four integer solutions, i.e. 1,0, - 1, - 2, then a should be between - 3 and - 2, i.e. - 3 ＜ a ≤ - 2, because finding out x ＜ 2, i.e. the largest integer of X is 1, and there are three forward numbers, i.e. 1,0, - 1, - 2, then the minimum of a is - 2 when a = -2.999 When a = - 3 does not work immediately - 3

To solve the system of linear equations of three variables, x minus y equals 6 2x plus 3Y equals Z 3x plus 2 y minus 3Z equals 2

X-Y = 6 (1) 2x + 3Y = Z (2) 3x + 2y-3z = 2 (3) (2) substitute into (3) eliminate Z to get: 3x + 2y-6x-9y = 2-3x-7y = 23x + 7Y = - 2 (4) (4) and (1) form binary linear equations (4) - (1) multiply by 3 to get: 10Y = - 20Y = - 2 substitute y = - 2 into (1) to get: x = 4 substitute y = - 2, x = 4 substitute into (2) to get: z = 2

3x + y + Z = 4 / 5, x + 3Y + Z = 0, x + y + 3Z = 6 / 5, how to solve the ternary linear equation by addition and subtraction? Headache!

3x+y+z=4/5 ①
x+3y+z=0 ②
x+y+3z=6/5 ③
① - 2, get 2x-2y = 4 / 5, then X-Y = 2 / 5 4
① In this case, 4x + y = 3 / 5
④ If + 5, we get 5x = 1,
The solution is x = 1 / 5
Substituting into 4, the solution is y = - 1 / 5
Substituting into 2, the solution is Z = 2 / 5

If x + 3zy = 3Y + ZX = 3x + YZ = k, then K=___ ．

The original formula can be reduced to x + 3Z = ky3y + Z = kx3x + y = KZ, adding the left and right sides of the three equations respectively to get: 4 (x + y + Z) = K (x + y + Z), (1) when x + y + Z ≠ 0, k = 4; (2) when x + y + Z = 0, x = - Y-Z, substituting x into the first two equations, we get, - Y-Z + 3Z = ky3y + Z = K (- Y-Z)

The solution equation: {x + y-3z = - 8, Z + y-3x = - 4, Z + x-3y = 12

Add three formulas
x+y-3z+z+y-3x+z+x-3y=-8-4+12
2x+2y+2z-3x-3y-3z=0
-x-y-z=0
x+y+z=0
x+y=-z
x+z=-y
y+z=-x
x+y-3z=-8
-z-3z=-8
4z=8
z=2
z+y-3x=-4
-x-3x=-4
4x=4
x=1
z+x-3y=12
-y-3y=12
4y=-12
y=-3
If you don't understand this question, you can ask,

3x + 3 / 7 = 10 / 7 solution process

3x + 3 / 7 = 10 / 7
3x=1
x=1/3

3x of 7 = 10 × 3 of 5,

3/7x=10*3/5
3/7x=6
x=6÷3/7
x=14

3x + 3 / 7 = 7 / 10

3x + 3 / 7 = 7 / 103x = 7 / 10-3 / 73x = 19 / 70X = 19 / 210 help each other

How to solve the equation 9:4 = 3x:5

9：4=3x：5
From the product of internal terms equal to the product of external terms
4 × 3x = 9 × 5
12x = 45
12x ÷ 12 = 45 ÷ 12
x = 3.75

5.26 + 0.3x = 3.4 (solution equation)

0.3x=3.4-5.56
0.3x=-1.86
x=-6.2