5/7x-6=1/4x+4

5/7x-6=1/4x+4

5/7x-6=1/4x+4
5/7x-1/4x=4+6
13/20x=10
x=200/13

5x > 4x-1, 7x + 2 is less than 5x-4

5x>4x-1
5x-4x>-1
x>-1
7x + 2 is less than 5x-4
7x-5x

4x-7x=9-5x x=?

4x-7x=9-5x
4x-7x+5x=9
2x=9
X = 9 / 2

How many jin is a liter of water?

One liter of water = 1kg = 2kg

96 divided by 2.3 when the quotient is 4.1, what is the remainder

96 divided by 2.3, when the quotient is 4.1, the remainder is: 96-2.3 * 4.1 = 86.57, which is illogical, because the remainder can not be greater than the divisor 2.3. So is the divisor 9.6, if it is 9.6, the remainder is 0.17.0.17 less than 2.3, that's right

Thank you, X2 = the square of X, y2 = the square of Y
The equation of one circle is x2 + y2 = 9, the other circle is x2-8x + y2-6y = 0, the line passing through the intersection of two circles is L1, and the line passing through point (5,4) and perpendicular to L1 is?

X2+Y2=9 （1）
X2-8X+Y2-6Y=0 （2）
From (1) - (2), the equation of the intersection line of two circles as L1 is 8x + 6y = 0, which is reduced to 4x + 3Y = 0
So the slope of the line is K-3 / 4, so the slope of the line is K-3 / 4
And because it's too much (5,4)
Y-4 = 3 / 4 (X-5)
That is to say, the linear equation is y = 3 / 4x + 31 / 4

1996 & sup3; + 1 divided by 1996 × 1997, the remainder is?

Analysis congruence principle:
The remainder of the original formula divided by 1996 * 1997 = the cube of 1996 divided by the remainder of 1996 * 1997 + 1 divided by the remainder of 1996 * 1997
And the remainder of 1 divided by 1996 * 1997 is 1
So we just need to find the remainder of 1996 * 1997 divided by the cube of 1996
1996*1996*1996/(1996*1997)
=1996*1996/1997
=(1997-1)(1997-1)/1997
=(1997*1997-1)/1997
Because the remainder of 1997 * 1997 divided by 1997 is 0, and the remainder of 1 divided by 1997 is 1
So the remainder of (1997 * 1997-1) / 1997 is 0-1
So the remainder of the original formula 1996 & sup3; + 1 divided by 1996 × 1997 is 0-1 + 1 = 0

A mathematical problem: if (x-1) (x + 1) (x + 5) = x2 + bx2 + CX + D, find the value of B + D (Note: X2 is the square of X, and so on)

I estimate that you may have made a mistake in the original question. After correction, the reasoning process is as follows:
(x-1)(x+1)(x+5)=x3+bx2+cx+d
(x2-1)(x+5)= x3+bx2+cx+d
x3+5x2-x-5= x3+bx2+cx+d
So: B + D = 5 + (- 5) = 0

200-800, X divided by 10, the remainder is 9, X divided by 9, the remainder is 8, divided by 8, the remainder is 7?

Known: X divided by 10, the remainder is 9, X divided by 9, the remainder is 8, divided by 8, the remainder is 7
So x is one less than the common multiple of 8,9,10
The least common multiple of 8,9,10 is 360
X is known to be between 200 and 800
200-800 has the common multiple 360 and 720 of 360
So x has two, 359 and 719

A mathematical problem: it is known that there is no intersection between hyperbola y = A / X (a is not equal to 0) and straight line y = - x + B. try to determine the conditions that a and B should satisfy
If you don't have a real root, you have to explain why

There is no intersection between hyperbola y = A / X (a is not equal to 0) and straight line y = - x + B,
The equation A / x = - x + B has no real roots
a=-x^2+bx
x^2-bx+a=0
Discriminant = B ^ 2-4a