60-5x = 7x-168 find the value of X?

60-5x = 7x-168 find the value of X?

7x+5x=60+168
12x=228
x=19

The process and result of 9 / 5x + 9 / 7X = 3x + 20 / 60

On the first floor, I think you are wrong
9/（5x）+9/（7x）=（3x+20）/60
The left general division becomes (9 × 7 + 9 * 5) / (35x) = the right (3x + 20) / 60
This equation is equivalent to: 35x (3x + 20) = 108 * 60 and X is not 0
21x^2+140x-1296=0
The solution is: x =

9x-3+2x+1=7x+60-5x+1

9x-3+2x+1=7x+60-5x+1 11x-2=2x+61 9x=63 x=7.

Given the function f (x) = x + 2 & nbsp; & nbsp; X ≤ 0 − x + 2 & nbsp; & nbsp; x > 0, then the solution set of inequality f (x) ≥ X2 is______ ．

When x ≤ 0, f (x) = x + 2, substitute the inequality to get: x + 2 ≥ X2, that is, (X-2) (x + 1) ≤ 0, the solution to get - 1 ≤ x ≤ 2, so the solution set of the original inequality is [- 1, 0]; when x > 0, f (x) = x + 2, substitute the inequality to get: - x + 2 ≥ X2, that is, (x + 2) (x-1) ≤ 0, the solution to get - 2 ≤ x ≤ 1, so the solution set of the original inequality is [0, 1]. In conclusion, the solution set of the original inequality is [- 1, 1], so the answer is The case is: [- 1, 1]

The sum of divisor, divisor, quotient and remainder is 178. Given that quotient is 4 and remainder is 22, what are the divisor and divisor respectively?

(178 - 4 - 22 - 22)÷（4+1）
=130÷5
=Divisor (26)
26×4+22
=104+22
=126 (divisor)

The inequality X & sup2; - (3a + 1) x + 2A (a + 1) ≤ 0

Factorization
(x-2a)[x-(a+1)]≤0
Zero 2a and a + 1
Compare their sizes
2a1
therefore
a

The sum of the divisor, divisor, quotient and remainder is 566. How much is the divisor and the divisor?
Sorry, I copied the wrong number. The sum of divisor, divisor, quotient and remainder is 866.

(866 - 22 - 8 -8)÷（22+1）
= 828 ÷23
=36 divisor
36 × 22 + 8 = 800 divisor

If a > b > C, a, B, C are constants, the solution set of inequality (x-a) (x-C) / (X-B) ^ 2 > 0 about X

（x-a)(x-c)/(x-b)^2>0
Because (X-B) ^ 2 > 0, two sides multiply it together to get:
(x-a)(x-c)>0
A > C
So the solution set is: x > A or X

The divisor divided by the divisor quotient is 22, the remainder is 8, the divisor quotient sum is 866, and the ball is divided by the divisor

Let X be the divisor, y be the divisor, x = 22y + 8, x + y + 22 = 886 be the system of equations

Find the largest constant K, so that for all real numbers ABCD in (0,1), there is an inequality a ^ 2 * B + B ^ 2 * C + C ^ 2 * D + D ^ 2 * a + 4 > k (a ^ 2 + B ^ 2 + C ^ 2 + D ^ 2)

k=0