The fourth power of X + the square of 7x-8 Such as the title

The fourth power of X + the square of 7x-8 Such as the title

The original formula = (x ^ 2) ^ 2 + (- 1 + 8) x ^ 2 + (- 1 * 8) = (x ^ 2-1) (x ^ 2 + 8) = (x + 1) (x ^ 2 + 8) if not clear, read 76 and 77 (Huige, more points)

Inequality 7x + X & # 178; + 8 < 0

7x+x²+8＜0
（x+7/2）²＜17/4;
∴-√17/2＜x+7/2＜√17/2;
∴-7/2-√17/2＜x＜√17/2-7/2;
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How to solve this problem

Because x (X-7) = 0, so x = 0 or X-7 = 0, so x = 0 or x = 7

x²+0.7x-0.78=0

X & # 178; + 0.7x-0.78 = 0 (x + 1.3) (x - 0.6) = 0, x = - 1.3 or x = 0.6 wuliangshou Buddha, the Buddha says the sea of bitterness is endless, and you will turn back to the shore! Benefactor, I see that you are a unique talent in the Wulin with a clear skeleton, magnificent appearance and wisdom. If you devote yourself to practice, you will become a great weapon in the future. I have a little test, please point out

Given 1 / X-1 / y = 3, what is the value of 2x-5xy-2y
Urgent a

1/x-1/y=(y-x)/xy=3
y-x=3xy
So X-Y = - 3xy
So the original formula = [(X-Y) - 2XY] of [2 (X-Y) - 5xy]
=[2 (- 3xy) - 5xy] of [(- 3xy) - 2XY]
=(- 5xy) (- 11xy)
=11 out of 5

The image with positive scale function y = - 5x and inverse scale function y = K / X (k is not equal to 0) intersects at point a (1, a). What is the inverse scale analytic expression and another intersection coordinate?

Substituting the point into the positive scale function y = - 5x,
A = - 5 can be obtained
So the coordinates of point a are (1, - 5)
Then a (1, - 5) is substituted into the inverse scale function y = K / X (k is not equal to 0)
We can get k = - 5
So the inverse function is - 5
Substituting y = - 5x into y = - 5 / X
Get - 5x = - 5 / X
The solution is x = 1, x = - 1
Substituting x = - 1 into y = - 5x yields y = 5
So the other intersection coordinate is (- 1,5)

Given that 1 / X-1 / y = 3, the value of x-2xy-y of 2x + 3xy-2y is

1/x-1/y=3
(y-x)/(xy)=3
y-x=3xy
(x-2xy-y)/(2x+3xy-2y)=[-(y-x)-2xy]/[-2(y-x)+3xy]=(-3xy-2xy)/(-6xy+3xy)=5/3

If the solution set of inequality system {X-2} is greater than or equal to a {x + 2} and greater than 3a is an empty set, then what is the value range of a?
Hurry!

X-2>=A
The solution set of X + 2 > 3a is empty
When a is a real number, the solution set of the above inequality system cannot be an empty set
So there is no such a, that is, the value range of a is an empty set

Given the real number x, y satisfies Y > = x ^ 2,2x ^ 2 + 2XY + y ^ 2

y=x^2>=0
2x^2+2xy+y^2

Given that the inequality 4x-3a is less than or equal to 0, the positive entire solution is 1,2,3, then what is the value range of a
emergency

4X less than or equal to 3A
X is less than or equal to 3A / 4
Because the positive entire solution is 1,2,3
So 3 is less than or equal to 3A / 4 is less than 4
4 less than or equal to a less than 16 / 3