Graph of first order function and quadratic equation of two variables The line y = KX + B crosses the point [- 6.0] and intersects the Y axis with the point B. the area of the triangle formed by the line and the two coordinate axes is 12! It's very simple, but I forgot that the final term will be finished in two days, There is another one. The image of the first-order function Y1 = k1-4 and the positive scale function y2 = k2x all pass through the point [2. - 1]. Find the area of the triangle surrounded by two Korean and X

Graph of first order function and quadratic equation of two variables The line y = KX + B crosses the point [- 6.0] and intersects the Y axis with the point B. the area of the triangle formed by the line and the two coordinate axes is 12! It's very simple, but I forgot that the final term will be finished in two days, There is another one. The image of the first-order function Y1 = k1-4 and the positive scale function y2 = k2x all pass through the point [2. - 1]. Find the area of the triangle surrounded by two Korean and X

Because (- 6,0)
So - 6K + B = 0
That is, B = 6K
It is easy to know that the intersection points of the two axes are (0, b) and (- B / K, 0)
Then the triangle area: S = | B | * | B / K | * 1 / 2 = | B | * 6 * 1 / 2 = 12
The solution is: | B | = 4
Then B = 4, k = 2 / 3 or B = - 4. K = - 2 / 3
Then the analytic formula is y = - 2x / 3-4 or y = 2x / 3 + 4

X = 2, y = 3 are the solutions of the system of equations x + y = 5, 2x-y = 1, so what are the coordinates of the intersection of the images of the linear functions y = 5-x and y = 2x-1?

Y = 5-x is x + y = 5
Y = 2x-1, that is, 2x-y = 1
So the intersection point of the image of the linear function y = 5-x and y = 2x-1 is the system of equations x + y = 5,2x-y = 1
Yes (2,3)

In the same rectangular coordinate system, we make the images of primary functions y = 2x-2 and 2Y = 4x-4. The relationship between the two images is as follows______ It can be seen that the solution of the system of equations 2x − y − 2 = 04x − 2Y − 3 = 0 is______ ．

Because 2Y = 4x-4 is reduced to y = 2x-2, which is the same as the analytic expression of the first-order function y = 2x-2, the relationship between the two images is coincident; the equation system 2x − y − 2 = 04x − 2Y − 3 = 0 can be transformed into 2x − y = 22x − y = 32, so the equation system 2x − y − 2 = 04x − 2Y − 3 = 0 has no solution