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A 120m long train passes through a 180m long bridge in 12s,
Train speed: (120 + 180) △ 12 = 300 △ 12 = 25m / S
A train passes at the same speed. A train passes two bridges at the same speed. The first bridge is usually 320 meters long and takes 24 seconds,
The second one is 440 meters. It took 30 seconds to find out how many meters this train can travel in one second and how long is its body?
（440-320）÷（30-24）
=120÷6
=20 m / S
20×30-440
=600-440
=160m
The train runs 20 meters in one second and its body is 160 meters long
There is a train passing the first and the second bridges at the speed of 600 meters per minute. It takes 5 seconds more to pass the second bridge than the first one. It is also known that the length of the second bridge is 50 meters shorter than that of the first bridge. Try to find the length of each bridge
Suppose the length of the first railway bridge is x meters, then the length of the second railway bridge is (2x-50) meters, and the time required to cross the first railway bridge is x600 minutes. The time required to cross the second railway bridge is 2x − 50600 minutes. According to the meaning of the question, the equation x600 + 560 = 2x − 50600 can be listed, and the equation x + 50 = 2x-50 is solved, and the result is x = 100, ∧ 2x-50 = 2 × 100-50 = 150
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