A monk walked to the railway station and walked 3km in the first hour. He looked at his watch and estimated that he would be 40 minutes late at this speed. Therefore, he walked 4km per hour Speed to take the rest of the road, the result is 45 minutes ahead of time to arrive, ask the person's home to the station distance?

A monk walked to the railway station and walked 3km in the first hour. He looked at his watch and estimated that he would be 40 minutes late at this speed. Therefore, he walked 4km per hour Speed to take the rest of the road, the result is 45 minutes ahead of time to arrive, ask the person's home to the station distance?

X X/3-40/60=（X-3）/4+1+45/60 x=2KM

Uncle Li took the train from his home to the railway station. He first walked at the speed of 50 meters per minute for 4 minutes. If he walked at this speed, he would be 16 minutes late and could not catch up. So he changed the speed to 60 meters per minute. As a result, he arrived at the railway station 10 minutes ahead of time?

Set the exact time to arrive as X minutes
Then (x + 16) × 50 = 50 × 4 + (x-4-10) × 60
50X+800=200+60X-840
10X=1440
X=144
So the distance from home to the railway station is (144 + 16) × 50 = 8000 meters