A mathematical problem in function and equation We know the equation x & sup2; - (m-2) x-m & sup2 / 4 = 0 about X. if the two real roots X1 and X2 of this equation satisfy | x2 | = | x1 | + 2, find the value of M and the corresponding X1 and x2

A mathematical problem in function and equation We know the equation x & sup2; - (m-2) x-m & sup2 / 4 = 0 about X. if the two real roots X1 and X2 of this equation satisfy | x2 | = | x1 | + 2, find the value of M and the corresponding X1 and x2


The discriminant of the equation = (m-2) ^ 2 + m ^ 2 > 0
So m is any value and the equation has two roots
According to Weida's theorem:
x1+x2=m-2 (1)
x1*x2=-m^2/4
For the square of | x2 | = | x1 | + 2, we get:
(| x2 | - | x1 |) ^ 2 = 4, i.e
x2^2+x1^2-2|x1*x2|=4
(x1+x2)^2-2x1*x2-2*|-m^2/4|=4
(m-2)^2-2*(-m^2/4)-2*(m^2/4)=4
The solution is as follows
M = 0, or M = 4
When m = 0, the equation is x ^ 2 + 2x = 0
So X1 = 0, X2 = - 2
When m = 4, the equation is x ^ 2-2x-4 = 0
So X1 = 1 - √ 5, X2 = 1 + √ 5



On trigonometric function, plane vector, probability, statistics, etc
Let AB be an acute angle, cosa = 4 / 5, Tan (a-b) = 1 / 3, and find the value of tanb
Question 2: the purchase price of each piece of clothing is 40 yuan. If the selling price of each piece is set at 70 yuan, it is estimated that 200 pieces can be sold, and if the selling unit price is reduced by 5 yuan, 50 more pieces can be sold. Question: how many pieces should be purchased? What is the selling price of each piece? What is the maximum profit? What is the maximum profit?
What's the probability of randomly selecting three products from three authentic products and two defective products?
If a line passes through point a (- 2. - 6) and is parallel to the x-axis, then the equation of the line is?
Question 4. Divide 8 students into two groups, 3 students in one group and 5 students in the other group?
If a + B = 4, what is (1 + Tana) multiplied by (1 + tanb)?


1. Cosa = 4 / 5, because it is an acute angle, so Sina = 3 / 5, Tana = 3 / 4tan (a-b) = (Tana tanb) / (1 + tanatanb) = - 1 / 3, so: (3 / 4-tanb) / (1 + 3 / 4tanb) = - 1 / 3 solution: tanb = 13 / 92, unit price reduced x 5 yuan (30-5x) (200 + 50x) = 250 (- x ^ 2 + 2x + 24) = 250 [- (x-1) ^ 2 + 25]



2 times 2012-9
[(28 + 0.5) + 1.3 times 5] divided by 1.4
2 and 7 / 20 divided by [5 and 3 / 5-4.5 times (20% + 1 / 3)]
It's easy. It's easy


[9 and 2012 / 2011 - (8-2012 / 1)] divided by 2 times 2 / 1 = (9 + 2011 / 2012-8 + 1 / 2012) / / 2 × 1 / 2 = (1 + 1) / / 2 × 1 / 2 = 1 / 2 [(28 + 0.5) + 1.3 times 5] divided by 1.4 = (28.5 + 6.5) / / 1.4 = 35 △ 1.4 = 252 and 20 / 7 divided by [5 and 5 / 3-4.5 times (20% + 3 / 1)] = 47 / 2