On the examples and examples of the area problems of quadratic equation of one variable It is an application problem of area of quadratic equation of one variable!

On the examples and examples of the area problems of quadratic equation of one variable It is an application problem of area of quadratic equation of one variable!


A village plans to build a rectangular vegetable greenhouse as shown in the figure. The ratio of length to width is required to be 2:1. In the greenhouse, 3M wide open space is reserved along the front inner wall, and 1m wide passage is reserved on the other three inner walls. When the length and width of the rectangular greenhouse are different, the area of vegetable planting area is 288 square meters? If the width is a meter, the length is 2A meters



Several mathematical problems, with the method of solving quadratic equation of one variable
1、3-27x²=0
2、4(1-x)²-9=0
3、x²-5x+6=0
4、8x²-2=4x
Solving quadratic equation with one variable by collocation method


1、3-27x²=0 x^2=9 x=3 x=-32、4(1-x)²-9=0 (1-x)^2=9/4 1-x=+-3/2 x=5/2 x=-1/23、x²-5x+6=0 (x-2)(x-3)=0 x=2 x=34、8x²-2=4x 8x²-4x-2=0 4x²-2x-1=0 4x²-...



How to solve the mathematical problem of quadratic equation with one variable?
To match a photo frame with a length of 29cm and a width of 22cm, the width of the four sides of the frame should be equal, the area of the frame should be one fourth of the photo area, and the width of the edge of the frame should be how many centimeters (the result retains one decimal place)? What I want is the process
According to the standard steps, it's better to have analysis-
First solution: let-------


If the edge width of the frame is x cm, the frame length is 29 + 2x and the frame width is 22 + 2x, so the frame area is (29 + 2x) (22 + 2x) - 29 * 22 = 29 * 22 / 4, that is 638 + 58x + 44x + 4x ^ 2-638 = 319 / 2, that is 8x ^ 2 + 204x-319 = 0, so x = (- 204 + radical 51824) / 16 = 1.5cm, or = (- 204 - radical 51824) / 16 (negative number, rounding off)