The fourth power of five (the third power of a) minus the second power of thirteen (the sixth power of a)

The fourth power of five (the third power of a) minus the second power of thirteen (the sixth power of a)
=The 12th power of 5A - the 12th power of 13A
=-The 12th power of 8A
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1. (4) - the fourth power of 1 - (the third power of 2 - 0.5 × 1 / 3) × (- 6) 2

0

-2 to the 2nd power + 3 * (- 1) to the 3rd power - (- 4) * 5 - (- 1 / 6 + 1 / 12) / - 1 / 48
=4-3+20-（-1/12÷-1/48）
=21-（-1/12*-48）
=21-4
=17

() to the third power = - 125 times 1 x to the 6th power y to the third power Compare the 18th power of size 2 with the 10th power of 2 × the 15th power of 3, the 50th power of 7 and the 25th power of 48, the 100th power of 2 and the 75th power of 3

The third power of (- 1 / 5 of X to the power of Y) = - 125 times 1 x to the 6th power of Y. compare the 18th power of 2 with the 10th power of 2 × the 15th power of 3, because the 18th power of 2 = the 10th power of 2 × the 8th power of 2 ∵ the 8th power of 2

It is known that the product of 3x's n minus 6 times Y's minus 2 minus n power and minus 1 / 3 x's 3m plus 1 times Y's 2n power and negative X's 4 It is known that the product of 3x's n minus 6 times Y's minus 2 minus n power and the product of minus 1 / 3 x's 3m + 1 times Y's 2n power and negative X's 4th power multiplication y are the same kind of items. Let's find the nth power of m plus the M power of N. please hurry up, thank you||||||||||||||||||||||||||||||

According to the meaning of the title:
∵ the product of n minus 6 power of 3x times y minus 2 minus n power and 3M plus 1 power of 1x minus 3 times y plus 2n power is the same as the product of 4 power of x minus y
∴n-6=3m+1=4
∴n=10 m=1
The nth power of m plus the m power of N. = the 10th power of 1 + the first power of 10 = 11

How to solve (2x's 6th power - X's 4th power) / (- 4x's 3rd power) + 4 (2x's 2x + 1) (4x's 2nd power - 2x + 1)

The first half = (2xxxxxx -- xxxxx) / (- XXX / 4) = - 4 (2xxxxxx - xxxxx) / (xxx) = - 8xxx + 4x, the latter half = 4 (x / 2 + 1 / 4) (4xx-2x + 1) = (2x + 1) (4xx-2x + 1) = 8xxx + 1 (note that this is the inverse change of AAA + BBB) before and after addition =

The 5th power of 3 × the 5th power of 5 × (- 1 / 15) to the 6th power

The 5th power of 3 × the 5th power of 5 × (- 1 / 15) to the 6th power
=The 5th power of 3 × the 5th power of 5 × (- 1 / 15) the 5th power of (- 1 / 15)
=To the power of (- 1 / 3 of ×)
=(- 1) to the 5th power × (- 1 / 15)
=1 in 15

What is the seventh power of minus 1001 times the sixth power of 0.125 times the seventh power of minus two seventh times the fourth power of thirteen times the seventh power of one eleventh worry

The 7th power of - 1001 times the 6th power of 0.125 times the 7th power of - 2 / 7 times the 6th power of - 13 / 4 times the 7th power of - 1 / 11
=(-1001)^7*0.125^6*(-2/7)^7*(-4/13)^6*(-1/11)^7
=-26

What's the remainder of 2007, 1001 divided by 13? 38 to the 101st power divided by 13. What's the remainder? Therefore, the explanation of the 1001st power of 70 * 27 + the 101th power of 31 * 38 can be divisible by 13

According to the binomial decomposition (38) ^ 101 = (39-1) ^ 101 = 39 * a + (- 1) ^ 101 = 39 * A-1 ﹥ 13mod (38) ^ 101 = 13mod (- 1) = 1270 * 27 ^ 1001 + 31 * 38 ^ 101 = 70 * (26 + 1) ^ 1001 + 31 * (39-1) ^ 101 = 70 * (13 * B + 1) + 31 * (13 * C + 12) = 13 * D + 70 + 31 * 12 = 13 * D + 13 * 34 ﹤ 70 * 27 ^ 1

-1001 to the seventh power x-0.125 to the sixth power X-2 / 7 to the seventh power x-4 / 13 to the seventh power X-1 / 11 to the seventh power Write down the specific process

=The seventh power of 1001 × the sixth power of 0.125 × the seventh power of 2 / 7 × the seventh power of 4 / 13 × the seventh power of 1 / 11
=The sixth power of (1001 × 1 / 8 × 2 / 7 × 4 / 13 × 1 / 11) × (1001 × 2 / 7 × 4 / 13 × 1 / 11)
=The sixth power of 1 × 8
=8

The fourth power of five (the third power of a) minus the second power of thirteen (the sixth power of a)