If cos alpha = 3 / 5, alpha belongs to (- π, 0), then cos (π / 4-alpha)

If cos alpha = 3 / 5, alpha belongs to (- π, 0), then cos (π / 4-alpha)

sinα=-4/5
cos(α-β)=cosα·cosβ+sinα·sinβ=3/5-4/5=-1/5

If the trigonometric function Tan (alpha + beta) = 2 / 5 and Tan (beta Pai / 4) = 1 / 4, then the value of Tan (alpha + 2 / 5) is?

Is to find the value of Tan (alpha + Pai / 4)
Tan (alpha + Pai / 4) = Tan [(alpha + beta) - (beta Pai / 4)]
=[Tan (alpha + beta) - Tan (beta Pai / 4)] / [1 + Tan (alpha + beta) · Tan (beta Pai / 4)]
=(2/5-1/4)/(1+2/5•1/4)
=3/22.

The trigonometric function has the following formula: sin (alpha + beta) = sin alpha cos beta + cos alpha sin beta According to this formula, we can get the sin75 degree

sin75=sin(30+45)
=sin30cos45+cos30sin45
=1/2*√2/2+√3/2*√2/2
=√2/4*(1+√3)

The period of y = (3 / 2) cos (1 / 2x - π / 6) x ∈ R,

In the function y = (3 / 2) cos (1 / 2 x - π / 6), ω = 1 / 2
So the period T = 2 π / 2 = 2 π / (1 / 2) = 4 π

Let f (x) = 2cos ^ 2 (x + π / 6) - cos ^ 2x (1) find the minimum value of F (x) and the minimum positive period (2) find that a, B, C are the three internal angles of △ ABC. If CoSb = 1 / 3, f (C / 2) = - 1 / 4, and C is an obtuse angle, find Sina Change: C for acute angle

1) F (x) = 1 + cos (2x + π / 3) - (1 + cos2x) / 2 = 1 / 2-sin2x radical 3 / 2
Minimum 1 / 2-radical 3 / 2
Minimum positive period π
2) C leads to sinc = root 3 / 2
C=π/3
A=π-B-C=2π/3-arccosB

If sin (π /6-x) =1/3, then cos (2 π /3+2x)=___________

cos(2π/3+2x)
=cos[π-(π/3-2x)]
=-cos(π/3-2x)
=-cos2(π/6-x)
=-[1-2sin²(π/6-x)]
=-[1-2*(1/3)²]
=-(1-2/9)
=-7/9

Given that the partial image of the quadratic function y = - x2 + 2x + m is shown in the figure, then the solution of the univariate quadratic equation - x2 + 2x + M = 0 is___ .

According to the meaning of the question, the symmetric axis of the quadratic function y = - x2 + 2x + m is x = 1, and the intersection point with the X axis is (3,0), / / the abscissa of the other intersection point of the parabola and the X axis is 1 - (3-1) = - 1, the intersection coordinate is (- 1,0)  when x = - 1 or x = 3, the function value y = 0, that is - x2 + 2x + M = 0,  on the one variable quadratic equation of X -... "

If the acute angle formed by the straight line y = 2x = 3 and the positive direction of X axis is a, and the acute angle formed by the straight line y = - 3x-1 and the positive direction of X axis is B, then the relationship between a and B is () AA is greater than B BA = B Ca ∠ B D cannot be determined PS I want more ideas. Thank you. The sooner the better Oh my God. It's true that the title is wrongly written /... 8. It's only after two digits that we can contact the function... Can we talk about it shallowly

Wrong title, I think it should be a straight line y = 2x + 3!
Make images and write their sine or cosine values
For example, Sina = 0.4 root sign 5
SINB = 0.3 root number 10
The sine function is an increasing function between [0 ° and 90 °]
Just compare the size of 0.4 root 5 and 0.3 root 10
So a

For the straight line y = - 2x + 3, y = - x, y = x, y = 4x-1, which one has the largest acute angle with the X axis and which has the smallest acute angle with the X axis, Can you find out the law? Please!

Calculate the slope k = - 2 / 1 - 1 / 1 1 / 1 4 / 1, take the larger the absolute value and the smaller the acute angle

Derivation of trigonometric function relation of mutual complementary angle

In a right triangle, there are angles a, B, C, and the corresponding sides are a, B, C. if C is 90 degrees, then a and B are mutually complementary. According to the definition of trigonometric function: Sina = A / C (opposite side to oblique side) CoSb = A / C (adjacent side to oblique side) both Sina = CoSb, that is, Sina = cos (90 degrees - a), which can be generalized