The radius of the inscribed circle of the square is R. find the radius of the circumscribed circle of the regular hexagon and its side length I've never learned a function to find the radius of the circumscribed circle and the length of its side. ... without functions

The side length of the square is 2R
The radius of the circumscribed circle of the square is √ 2 * r
Where did this regular hexagon come out

The radius of the inscribed circle of a regular hexagon is r

That is to say, the distance from the center of the circle to the edge: the distance from the center of the circle to the fixed point =?
As long as you draw a picture, draw these two lines to form a triangle. It is easy to know that the angle of the triangle at the center of the circle is 30 degrees, so this ratio is the root of 3:2

In the macro block R1 = R6 / r2-r3 * cos (R4); the priority operation is (). (Siemens system) A function: cos (R4) B. multiply: R3 * C. subtract: R2 - D. divide: R6/

In the circuit shown, it is known that RL = R2 = 8 Ω, R3 = R4 = 6 Ω, R5 = R6 = 4 Ω, R7 = R8 = 24 Ω, R9 = 16 Ω, circuit terminal voltage U = 224v, try to find the current passing through resistance R9 and the voltage at both ends of R9? I total → R1 → R3 → R5 ↓ ↓ ↓ R7 R8 R9 ↓ ↓ ↓ ← R2 ← R4←←←R6 ← First level members do not allow the transmission of the diagram, so they use the arrow to represent the wire and R to represent the resistance. A simple drawing is drawn. Please help to solve the current I of R9 I total-r1-r3 ┄ R5 - ↓ ↓ ↓ R7 R8 R9 ↓ ↓ ↓ ┈— R2——R4———R6┘

The whole circuit is R5, R9, R6 in series and then paralleled with R8. The obtained equivalent resistance is connected in series with R3 and R4, and then in parallel with R7. The equivalent resistance of R1, R2 in series with R5, R6, R8, R9 = (R5 + R6 + R9) | R8 = 12 Ω (| is in parallel) R3, R4, R7 and 12 Ω equivalent resistance = (R3 + R4 + 12) | R7 = 12 Ω, R1 + R2 + 12 = 28 Ω, so R7 is powered on

The largest square area in a circle is 20 square centimeters. Find the area of the circle emergency

When the square radius is 20.3 cm, the area of the inner circle is 10.4 cm

As shown in the figure, the area of the square is 20 square centimeters. The shadow part is the largest circle in the square

Let the side length of a square be a, then A2 = 20 square centimeters,
The area of the circle is π (a △ 2) 2,
=3.14×a2
4，
=3.14×5，
=15.7 (square centimeter);
A: the area of the circle is 15.7 square centimeters

The area of a square with the radius of a circle as its side length is 20 square centimeters

Let the radius of the circle be r, then R ^ 2 = 20cm ^ 2
Therefore, the circular area = 3.14r ^ 2 = 3.14 * 20 = 62.8cm ^ 2

The radius of a circle is equal to the side length of a square. The area of a square is 20 square centimeters. What is the area of a circle? I figured it out to be 62.8. But my classmates said they couldn't

If the square area is 20, the side length is 2 pieces and 5 cm
So the radius of the circle is two, five centimeters
The circle area is 3.14 * 20 = 62.8
You're right. Hey

The area of the largest square in a circle is 20 square centimeters. Find the area of the circle

3.14×（20/4）
=3.14×5
=15.7 square centimeter

Draw the largest square in a circle. Its area is 12 square meters. Find the area of the circle

12 / 4 = 3 square meters divides the square into four right triangles
3 * 2 * 3.14 = 18.84 square meters 3 * 2 is the radius of the circle multiplied by the radius
A: the area of the circle is 18.84 square meters

The radius of the inscribed circle of the square is R. find the radius of the circumscribed circle of the regular hexagon and its side length I've never learned a function to find the radius of the circumscribed circle and the length of its side. ... without functions