As shown in the figure, △ ABC is a right triangle, ∠ C = 90 °, CA = CB, ad bisect ∠ BAC, de ⊥ AB, if AB = 18cm, calculate the circumference of △ DBE

As shown in the figure, △ ABC is a right triangle, ∠ C = 90 °, CA = CB, ad bisect ∠ BAC, de ⊥ AB, if AB = 18cm, calculate the circumference of △ DBE

∵ ad is the angular bisector of ∵ cab, and de ⊥ ab ∵ C = ∵ AED = 90 degrees and DC = de (the distance from the bisector to the two sides of the angle is equal), and ad = ad, so △ ACD ≌ △ AED,

In the triangle ABC, the angle c = 90 °, CA = CB, ad bisect the angle BAC?

Make de perpendicular AB and intersect AB at point E, that is to say
Triangle ACD and AFD congruence,
DE=DC,AC=AE,
The perimeter of BDE = BD + de + be = BD + DC + be = BC + be = AC + be = AE + be = ab

If ∠ C = 90 ° in △ ABC, CA = CB, ad bisection ∠ cab intersecting BC on D, de perpendicular to AB on e, and ab = 6, then what is the circumference of △ DEB?

∵ ad bisection ᙽ cab intersects BC on D, De is perpendicular to e,

In △ ABC, ∠ C = 90 °, AC = BC, ad is the bisector of ∠ BAC, de ⊥ AB, and the perpendicular foot is e. if AB = 12cm, then the circumference of ⊥ DBE is () A. 12cm B. 10cm C. 14cm D. 11cm

∵ ad is the bisector of ⊥ BAC, de ⊥ AB, ∵ C = 90 ∵
Easy to get △ ACD ≌ △ AED
∴CD=DE，AE=AC
The circumference of △ DBE = de + EB + be = CD + DB + EB = BC + EB = AC + EB = AE + EB = AB = 12cm
Therefore, a

In the triangle ABC, the angle c = 90 degrees, AC = BC, ad is the bisector of the angle BAC, De is vertical AB, and the perpendicular foot is e. if ab-10cm, calculate the circumference of the triangle DBE

From AD is the bisector of the angle BAC
Angle CAD = angle EAD
Because De is vertical ab
So angle ACD = angle DEA = 90 degrees
Ad is the common side
So triangle ACD congruent triangle AED
So AC = AE
AC = BC
So AC = CD + dB
From ab = AE + EB
So AB = AC + EB
AB=CD+DB+EB=10
CD + DB + EB is the perimeter of the triangle DBE
Perimeter of triangle DBE = 10 (CM)

As shown in the figure, in the triangle ABC, the angle c = 90 degrees, AC = BC, ad is the bisector of the angle BAC, De is perpendicular to AB and E, if AC = 10 cm, the perimeter of the triangle DBE is equal to

In the triangle ABC, the angle c = 90 degrees, AC = BC, ad is the bisector of the angle BAC, De is perpendicular to AB and E. if AC = 10 cm, the circumference of the triangle DBE is equal to 10 root signs 2cm
The circumference of triangle DBE = BD + be + DC = CD + BD + be = BC + be = AE + be = ab

In △ ABC, if BC = 20cm, be = 7.6cm, then the circumference of △ DBE is______ cm．

∵ C = 90 °, AC = BC, ad bisection ∵ BAC to BC to D, de ⊥ ab
∴DC=DE
The circumference of △ DBE is DB + be + de = BD + CD + be = BC + be = 27.6cm
Therefore, fill in 27.6

In the triangle ABC, the angle c = 90 degrees, AC = BC, ad bisect angle BAC, De is perpendicular to AB and E. if AB = 20, what is the circumference of the triangle DBE If you don't understand the root sign when the picture comes out, what do you think is wrong? How do I feel that what I draw is different from what you said

The unit of circumference is degree?
If it's perimeter, it's 20
Perimeter = BD + ed + BC
=BD+CD+BE
=AC+BE
=AE+BE
=AB
=20

Right triangle ABC, angle c = 90, AC = BC, ad is the bisector of angle BAC, AE = BC, De is perpendicular to AB, and the perpendicular foot is e. it is proved that the circumference of triangle DBE is equal to ab

Proof: ∵ bad = ∵ CAD
ν de = CD. (properties of angular bisectors)
Therefore, BD + de + EB = BD + CD + EB = BC + EB;
AE = BC. (known)
Therefore, BD + de + EB = AE + EB = ab

In the triangle ABC, the angle c = 90 degrees, AC = BC, ad bisector angle ∠ cab intersects BC in D, De is perpendicular to AB in E. if AB = 6cm, then the circumference of △ DBE is?

﹤ C = 90 ° CA = CB, ﹤ cab is an isosceles right angle △,
 B = 45 ° and ﹤ DEB is also an isosceles right angle △,
∴DE=BE,
∵ ad is the angular bisector, ᙽ DC = De,
∴AC=AE,
ν△ DEB perimeter = de + be + DB
=DC＋DB＋BE
=CB＋BE
=AE＋EB
=AB
=6㎝,
The circumference of △ DEB = 6cm