NaHCO3(small amount)+ Ca (OH)2 and NaHCO3(excess)+ Ca (OH)2

NaHCO3(small amount)+ Ca (OH)2 and NaHCO3(excess)+ Ca (OH)2

NaHCO3(small amount)+Ca (OH)2===CaCO3 precipitation+H2O+NaOH
2NaHCO3(excess)+Ca (OH)2====CaCO3 precipitation+Na2CO3+2H2O

NaHCO3(small amount)+ Ca (OH)2=== CaCO3 precipitation + H2O + NaOH
2NaHCO3(excess)+Ca (OH)2====CaCO3 precipitation +Na2CO3+2H2O

How to write the specific reaction equation of Ca (HCO3)2 and NaOH in different amounts?

If NaOH is excessive, Ca (HCO3)2+2NaOH=CaCO3+Na2CO3+2H2O;
If NaOH is insufficient, then Ca (HCO3)2+NaOH=CaCO3+NaHCO3+H2O.
The writing of the ion equation is based on a small quantity.