How to write the ion equation of excess Ca (HCO3)2 solution with NaOH solution?

How to write the ion equation of excess Ca (HCO3)2 solution with NaOH solution?

Since Ca (HCO3)2 is excessive, HCO3- can not be completely reacted. The chemical equation is:
Ca (HCO3)2+NaOH=CaCO3 NaHCO3+H2O
The ion equation is: Ca^2++HCO3-+OH^-==CaCO3 H2O

Drop a small amount of NaOH solution into the excess Ca (HCO3)2 solution to the reaction ion equation

Ca2+OH-+HCO3-=CaCO3 precipitation+H2O