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Given that a, b, c are all integers, and the third power of the absolute value of a-b + the square of the absolute value of c-a=1, the absolute value of a-c + the absolute value of c-b + the absolute value of b-a is obtained Given that a, b, c are all integers, and the third power of the absolute value of a-b + the square of the absolute value of c-a=1, find the absolute value of a-c + the absolute value of c-b + the absolute value of b-a Given that a, b, c are integers, and the third power of the absolute value of a-b + the square of the absolute value of c-a=1, the absolute value of a-c + the absolute value of c-b + the absolute value of b-a is obtained
|A-b |^3+|c-a |^2=1 is the third power of x an integer, there are only two cases:(1)|a-b |=0;|c-a |=1=> a=b;|c-a |=1(2)|a-b |=1;|c-a |=0=> a=c;|a-b |=1, then (1)|a-c |+|c-b |+|b-a |=|a-c...
If the absolute value of the quadratic +b+1 of (2a-1)=0, then the quadratic +1/b of 1/a is to the 2009 power
The quadratic sum |b+1| of (2a-1) is greater than or equal to 0,
2A-1=0, b+1=0
A=1/2, b=-1
1/A quadratic =2 2=4 1/b 2009=-1^2009=-1
The original formula =4+(-1)=3.
The quadratic sum |b+1| of (2a-1) is greater than or equal to 0,
2A-1=0, b+1=0
A=1/2, b=-1
1/A quadratic =2 2=4 1/b 2009=-1^2009=-1
The formula =4+(-1)=3.
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