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Given a is the smallest positive integer, b, c is a rational number, and |2+b|+(a+c)2=0. Find the formula 4ab+c Given that a is the smallest positive integer, b, c is a rational number and has |2+b (a+c)2=0. Find the value of the formula 4ab+c/-a2+c24.
It is known that a is the smallest positive integer, b and c are rational numbers, and there is |2+b (3a+2c)*(3a+2c)=0 find the formula 4ab+c*-a*-a+c*c+4 Given a is the smallest positive integer, b, c is a rational number, and has |2+b (3a+2c)*(3a+2c)=0 find the formula 4ab+c*-a*-a+c*c+4
A is the smallest positive integer
A =1
|2+B (3a+2c)2=0
Then b=-2, c=-3/2
4Ab+c*-a*-a+c*c+4
=-8-3/2+9/4+4
=-13/4
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