Given that the real number a satisfies |2008-a root a-2009=a, find the value of a-2008^2

Given that the real number a satisfies |2008-a root a-2009=a, find the value of a-2008^2

It's a great question, and I almost ca n' t hold it.2008-a (a-2009)=a. To make the equation meaningful, a-2009≧0. a≧2009>2008 so that |2008-a|<0.2008-a|=a-2008 can be transformed into: a-2008(a-2009)=a 2008=√(a-200...

This is a great question, and I almost couldn't 2008-a (a-2009)=a. To make the equation meaningful, a-2009≧0. a≧2009>2008 so that |2008-a|<0.2008-a|=a-2008 can be transformed into: a-2008(a-2009)=a 2008=√(a-200...

Three non-equivalent rational numbers can be expressed in the form of 1, a+b, a, or 0, a parts b, b. Try to find the power of 2007+b of 2008 of a Value of power Three non-equivalent rational numbers can be expressed in the form of 1, a + b, a, or 0, a parts b, b. Try to find the power of a in 2007+ b in 2008 Value of power

Since the three are not equal, the possible scenarios are:
1)0= A,
2)0= A + b
When a =0, a/b =0, then 0, a/b, b are not three non-equivalent rational numbers (because 0= a/b)
So a=0 is impossible
A+b=0 gives a/b=-1, so {0,-1, b}
And {1, a+b, a} and {0,-1, b} are equal, a+b=0, so a=-1, b=1
A^2007+b^2008=-1+1=0