Given the root number a+1+ root number b+1=0(a, b are real numbers), find the value of 100th power of a +101th power of b.

Given the root number a+1+ root number b+1=0(a, b are real numbers), find the value of 100th power of a +101th power of b.

It is easy to know that both that root a+1 and the root b+1 are number that are greater than or equal to 0,
Then they should all be equal to 0, a =-1 b =-1
100 Of a equals 1 and 101 of b equals -1
So sum is 0

It is easy to know that both that root a+1 and the root b+1 are number that are greater than or equal to 0,
Then they should all be equal to 0, a =-1 b =-1
100 Of a equals 1 and 101 of b equals -1
So and are 0

It is easy to know that both that root a+1 and the root b+1 are number that are greater than or equal to 0,
Then they should all be equal to 0, a =-1 b =-1
100 Power of a equals 1 and 101 power of b equals -1
So and are 0

(3+Root 10) by (3-Root 10)

(3+Root 10) by (3-Root 10)
=100Th power of (3+Root 10)(3-Root 10)
=[(3+Root 10)*(3-Root 10)]^100*(3-Root 10)
=(9-10)^100*(3-Root 10)
=3-Root 10

(3+Root 10) to the 100th power of (3-Root 10) to the 101st power of
=100Th power of (3+Root 10)(3-Root 10)
=[(3+Root 10)*(3-Root 10)]^100*(3-Root 10)
=(9-10)^100*(3-Root 10)
=3-Root 10