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Given the quadratic of |a+2(b-5)=0, then B of A =?
The fifth power of a =-2 b =5-2 is -32
1+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+ 1+2+2+2+3+2+4+...+2+2013 Solution; let s =1+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2 2S=2+2+2+3+2+4+2+5+...+2+2013+2-2014 Subtract 2s-s=2 from the following equation to the power of 2014-1 I.e.2014 power-1 of s=2 I.e.1+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+2+ Calculate the 2nd power of 1+3+3+3 third power +3 fourth power +...+3 nth power (where n is a positive integer)
Let s=1+3+3+3+3+3+3+3+4+...+3+n
Multiply both sides by 3 simultaneously to:
3S=3+3 to the second power +3 to the third power +3 to the fourth power +...+3 to the nth power +3 to the (n+1) power
Subtract (n+1)-1 of 3s-s=3 from the following equation
S =(3 to (n+1)-1)/2
Let s=1+3+3+3+3+3+3+3+4+...+3+n
Multiply 3 on both sides simultaneously to:
3S=3+3 to the second power +3 to the third power +3 to the fourth power +...+3 to the nth power +3 to the (n+1) power
Subtract (n+1)-1 of 3s-s=3 from the following equation
S =(3 to (n+1)-1)/2
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