S=1+2 negative first power +2 negative second power +2 negative third power ++2 negative 2005 power, how much is S equal? Understand, Junior Two ~~~~~ Is this a multiplication? S=1+2 negative first power +2 negative second power +2 negative third power ++2 negative 2005 power, how much is S equal? Understand, Junior Two ~~~~~ Excuse me: Is this a multiplication?

S=1+2 negative first power +2 negative second power +2 negative third power ++2 negative 2005 power, how much is S equal? Understand, Junior Two ~~~~~ Is this a multiplication? S=1+2 negative first power +2 negative second power +2 negative third power ++2 negative 2005 power, how much is S equal? Understand, Junior Two ~~~~~ Excuse me: Is this a multiplication?

S=1+2^-1+2^-2+...+2^-2005
=(1/2)^0+(1/2)^1+(1/2)^2+…+(1/2)^2005
=(1-(1/2)^2006)/(1-(1/2))
=2-(1/2)^2005

S=1+2-1+2-2+...+2-2005
=(1/2)^0+(1/2)^1+(1/2)^2+…+(1/2)^2005
=(1-(1/2)^2006)/(1-(1/2))
=2-(1/2)^2005

S=1+2+2+2+2+the third power of 2+...+2, find the value of S. S=1+2+2+2+2+the third power of s+...+2 is the 2005 power of s.

This is actually a sum of proportional numbers.
1 Is the nilpotent of 2
2 Is a power of 2
So, it's a sequence of equal-ratio numbers that starts with the zero power of 2 and ends with the 2005 power of 2.
According to the equation a1(1-q^n)/(1-q) where a1=1q=2n=2006(q^n is the power of q)
So we end up with a 2006 power of 2 minus 1

This is actually a sum of proportional numbers.
1 Is the nilpotent of 2
2 Is a power of 2
So, it's a sequence of equal-ratio numbers that starts with the zero power of 2 and ends with the 2005 power of 2.
According to the equation a1(1-q^n)/(1-q) where a1=1q=2n=2006(q^n is the power of q)
So it turns out that the final result is the 2006 power of 2 minus 1