Given that the side lengths of triangles abc are abc and abc satisfies the root number a minus three plus the absolute value of b-4+ c-5, the square of c-5 is equal to 0, try to find the shape of triangle ABC? Given that the side lengths of triangles abc are abc and abc satisfies the root number a minus the absolute value of three plus b-4+ c-5, the square of c-5 is equal to 0, try to find the shape of triangle ABC? Given that the side lengths of triangles abc are abc and abc satisfies the root number a minus three plus the absolute value of b-4+ the square of c-5 is equal to 0, try to find the shape of triangle ABC?

Given that the side lengths of triangles abc are abc and abc satisfies the root number a minus three plus the absolute value of b-4+ c-5, the square of c-5 is equal to 0, try to find the shape of triangle ABC? Given that the side lengths of triangles abc are abc and abc satisfies the root number a minus the absolute value of three plus b-4+ c-5, the square of c-5 is equal to 0, try to find the shape of triangle ABC? Given that the side lengths of triangles abc are abc and abc satisfies the root number a minus three plus the absolute value of b-4+ the square of c-5 is equal to 0, try to find the shape of triangle ABC?

Root number (a-3)+ absolute value of b-4+(c-5)2=0
Root number (a-3)≥0
Absolute value of b-4≥0
(C-5)2≥0
A=3, b=4, c=5
∵3²+4²=5²
ABC is a right triangle

Absolute value of root number (a-3)+b-4+(c-5)2=0
Root number (a-3)≥0
Absolute value of b-4≥0
(C-5)2≥0
A=3, b=4, c=5
∵3²+4²=5²
ABC is a right triangle

Given that a.b.c satisfies the absolute value of a-root 8, plus root b minus root 18 plus bracket c minus square of root 32 equals 0 to the value of abc

|A-√8 b-√18+(c-√32)2=0
| A-√8|+(c-√32)2>=0
Therefore, the three terms are equal to 0 can be established.
A=√8, b=√18, c=√32
Then, abc=√8√18√32)=16√18