3' S 1999 power-5*3's 1998 power +6*3's 1997 power-1999* negative 1's 1999 power The one up there is wrong. It should be 3' S 1999 power-5*3's 1998 power +6*3's 1997 power +1999*'s negative 1's 1999 power 3' S 1999 power-5*3's 1998 power +6*3's 1997 power-1999* negative 1's 1999 power The one up there is wrong. 3' S 1999 power-5*3's 1998 power +6*3's 1997 power +1999*'s negative 1's 1999 power

3' S 1999 power-5*3's 1998 power +6*3's 1997 power-1999* negative 1's 1999 power The one up there is wrong. It should be 3' S 1999 power-5*3's 1998 power +6*3's 1997 power +1999*'s negative 1's 1999 power 3' S 1999 power-5*3's 1998 power +6*3's 1997 power-1999* negative 1's 1999 power The one up there is wrong. 3' S 1999 power-5*3's 1998 power +6*3's 1997 power +1999*'s negative 1's 1999 power

3^1999-5×3^1998+6×3^1997+1999×(-1)^1999 Original expression =3^1997×(3^2-5×3+6)+1999×(-1)=3^1997×(9-15+6)-1999=3^1997×0-1999=-1999 Final answer is -1999.Note: In a computer,^ means how many power, for example,3^1997 means...

The cube of 1 plus 2 plus 2 plus 2 always adds to the power of 2 in 1999 Explain the truth, high school algorithm is not good

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