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Given |x-1|=4, if the absolute value of x-1 is equal to 4, find X and observe that the distance between the point representing the number X on the number axis and the point of 1 is suitable under the heuristic of 1 1<|X-1|<4 All integers
A solution of |x-1|=4 is 5 or -3, and the solution set {5,-3} is all the sets of points with a distance of 1 to 4. In other words, the inequality |x-1|=4 is equivalent to the "set of points with a distance of 4 to 1". Similarly,1<|x-1|<4 and the" set of points with a distance of 1 between intervals (1,4)" are equivalent. Only {3,4,-1,2}
Given that point A is -4 on the number axis and point B is 1, let P be the number corresponding to X on the number axis, when the absolute value of PA - the absolute value of PB is equal to 2, find the value of X.
|X+4|-|x-1|=2
X >1 x+4-x+1=2 does not hold
-4
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