1+X+X squared +x cube +X 2004 power +X 2005=0, then x 2006=?

X^2006-1=(x-1)(1+x+X squared+x cube+X 2004 power+X 2005)
Because 1+x+X squared +x cube +X 2004 power +X 2005=0
So x^2006-1=0
So x^2006=1

Given the square of x + x +1=0, find the 2006 power of x + the 2005 power of x +…… +X squared +x+1

Three in a group.
Original formula =2004 power of x (x2+x+1)+2001 power of x (x2+x+1)+...... +(X2+x+1)
=0+0+…… +0
=0

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