Given the 2nd power of a+a+1=0, find the value of the 2006 power of a+a and the 2005 power of a+a and the 2004 power of a

Given the 2nd power of a+a+1=0, find the value of the 2006 power of a+a and the 2005 power of a+a and the 2004 power of a

A 2006+a 2005+a 2004
= A^2004(a^2+a+1)
=A^2004*0
=0

2006 Power of a +2005 power of a +2004 power of a
= A^2004(a^2+a+1)
=A^2004*0
=0

A 2006+ a 2005+ a 2004
= A^2004(a^2+a+1)
=A^2004*0
=0

(The square of x+X+1)=0, then what is the 2006 power of X + the 2005 power of X + the 2004 power of X A rectangle with an area of X squared +2X-35 and a known width of X-5, why is it long?

2006 Power of X +2005 power of X +2004 power of X
=2004Th power of X ×(square of x + X+1)
=2004 Power of X ×0
=0