Given that the square of x plus 2 x is equal to 3, fourth power of x plus the third power of 7 x plus the square of 8 x minus 13 x plus 2009 Given that the square of x plus 2x equals 3, then the fourth power of x plus the third power of 7x plus the square of 8x minus 13x plus 2009

Given that the square of x plus 2 x is equal to 3, fourth power of x plus the third power of 7 x plus the square of 8 x minus 13 x plus 2009 Given that the square of x plus 2x equals 3, then the fourth power of x plus the third power of 7x plus the square of 8x minus 13x plus 2009

Factorization
X^2+2x-3=(x-1)(x+3)=0
Solution x=1 or x=-3
Substitute the required formula (4th power of x plus 3th power of 7x plus 8x squared minus 13x plus 2009)
Turns out it was all 2012.
Algebraic methods.

Let (2-1)(2+1)(the square of 2+1)(the 4th power of 2+1)...(the 32nd power of 2+1)+1. A hundred percent is yours! Answer with Knowledge of Square Difference] In fact, it's the sixth question on page 57 of the math book for the first day of the beijing model edition Let (2-1)(2+1)(the square of 2+1)(the 4th power of 2+1)...(the 32nd power of 2+1)+1. A hundred points is yours! Answer with Knowledge of Square Difference] In fact, it's the sixth question on page 57 of the math book for the first day of the beijing model edition

(2-1)(2+1)(2 Squared+1)(2 quartered+1)...(2 quartered+1)+1=(2 quartered+1)(2 quartered+1)(2 quartered+1)...(2 quartered+1)+1=(2 quartered+1)(2 quartered+1)...(2 quartered+1)...(2 quartered+1)...(2 quartered+1)+1=(2 quartered+1)...(2 quartered+1)+1=(2 quartered+1)...(2 quartered+1)+1=(2 quartered+1)...(2 quartered+1)...(2 quartered+1)...

(2-1)(2+1)(2 Squared+1)(2 quartered+1)...(2 quartered+1)+1=(2 quartered+1)(2 quartered+1)(2 quartered+1)...(2 quartered+1)+1=(2 quartered-1)(2 quartered+1)...(2 quartered+1)...(2 quartered+1)...(2 quartered+1)+1=(2 quartered+1)...(2 quartered+1)+1=(2 quartered+1)+1=(2 quartered+1)+1=(2 quartered+1)...