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The second power of the absolute value of 3x+1+(Y+1) is equal to 0, and the following values are obtained:(1) the value of xy;(2) the third power of -x plus the value of 2012. The second power of absolute value +(Y+1) of 3x+1 is equal to 0, find:(1) the value of xy;(2) the third power of -x plus the value of 2012. The second power of the absolute value +(Y+1) of 3x+1 is equal to 0, and we find:(1) the value of xy;(2) the third power of -x plus the value of 2012.
The two numbers add up to zero, because both are positive, so the absolute value of 3x+1 is 0, and the absolute value of y+1 is zero, so=-1/3, y=-1, so xy is 1/3, and the answer is 26/27
If the absolute value of x minus 1 plus the 2th power of y minus 2 equals 0, then what is the 2009 power of x minus y
X-1(y-2)2=0
X-1=0 y-2=0
X =1 y =2
(X-y)^2009=(1-2)^2009=(-1)^2009=-1
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