2006 Power of trial judgment 2 multiplied by 2007 bit number of 3

2006 Power of trial judgment 2 multiplied by 2007 bit number of 3

Judgement 2's 2006th power multiplied by 3's 2007th power's individual digit number, is actually a mantissa problem, the mantissa problem must find the law of the power. The mantissa of 2 is itself, so judge 2's power law.2(mantissa 2)2×2(mantissa 4)2×2×2×2(mantissa 8)2×2×2×2(mantissa 6)2×2×2×2×2(mantissa 6)2×2×2×2(mantissa...

2007 Power of [-1/5] multiplied by 2006 power of [-5]=?

2007 Power of [-1/5] multiplied by 2006 power of [-5]
=(-1/5*-5)^2006*(-1/5)
=1*-1/5
=-1/5

[-1/5]-1/5] Multiplied by 2006 power of [-5]
=(-1/5*-5)^2006*(-1/5)
=1*-1/5
=-1/5