Using the 2005 power of factorization 2 minus the 2006 power of 2 equals?

Using the 2005 power of factorization 2 minus the 2006 power of 2 equals?

2^2005-2^2006
=2^2005*(1-2)
=-2^2005

Factorization calculation (2005 third power-2*2005 second power-2003)/(2005 third power+2005 second power-2006) 2005 Cubic minus 2 x 2005 2 minus 2003/2005 cubic +2005 2 minus 2006(calculated using factorization)(process)

Let x=2005(2005 third power-2*2005 second power-2003)/(2005 third power+2005 second power-2006)=(x3-2x2-x+2)/(x3+x2-x-1)=(x-2)(x2-1)/(x+1)(x2-1)=(x-2)/(x+1)=(2005-2)/(2005+1)=2003/2006...