Given the position of rational number a.b.c. on the number axis as shown in the figure,|a|=|b|1.a+b and a/b values;2. sign of c-a/c-b and bc (a+c)(b+c)3 values;3. simplify |a+b|-|a-b|-|c-a|+2|c-b||a+c|-|-|b|. What if we don't? ____.________.__.____.___________ A b0c

Given the position of rational number a.b.c. on the number axis as shown in the figure,|a|=|b|1.a+b and a/b values;2. sign of c-a/c-b and bc (a+c)(b+c)3 values;3. simplify |a+b|-|a-b|-|c-a|+2|c-b||a+c|-|-|b|. What if we don't? ____.________.__.____.___________ A b0c

First of all, the position of this 0 is not right~0 must be between a and b, because this picture is drawn by you, I don't know whether the distance between abc is equal, as far as I can understand, abc interval should be equal~
Well, I'll do it my way.
A:
|A|=|b|-->-a = b
1 A + b =0, a/b =-1
2 Set b as t, a =-t, because a and b and c are equally spaced, b-a = c-b --> t is brought into c =3t, and abc is brought into c -a/c -b =2; bc (a+c)(b+c)3>0
3 Method as above, bring abc into 3b
I don't know if it's right, but there's something wrong with it.

The position of rational numbers a, b, c on the number axis is shown in the figure,——B——A——0——C——1 if M=|a+b|-|b-1|-|a-c|-|1-c|, then What is the power of 2009 multiplied by (m+1)+1+=

M=|a+b|-|b-1|-|a-c|-|1-c|
=(-A-b)-(1-b)-(c-a)-(1-c)
=-A-b-1+b-c+a-1+c
=-2
(M+1)=-1
2009 Multiplied by (m+1)2009 power +1=-2009+1=-2008