Given that the square of x minus x minus 1 equals 0, the third power of negative x plus 2x plus 2011

Given that the square of x minus x minus 1 equals 0, the third power of negative x plus 2x plus 2011

-X3+2X+2011
=-(X3+1)+2X+2012
=-(X+1)(X2-X+1)+2X+2012
Since X2-X-1=0, then X2-X=1 is substituted into the above formula, then:
Original formula=-2X-2+2X+2012=2010

Given that a and b are mutually opposite numbers, c and d are mutually reciprocal, and the second power of (x+1)=0. Try to find the value of the third power of x +(a+b) of the 2009 power -(-cd) of the 2008 power?

A and b are mutually opposite numbers
A+b=0
C and d are reciprocal
Cd =1
(X+1)2nd power =0
X=-1
X^3+(a+b)^2009-(-cd)^2008
=-1+0-1
=-2

A and b are mutually opposite numbers
A+b=0
C and d are reciprocal
Cd =1
(X+1) to the second power =0
X=-1
X^3+(a+b)^2009-(-cd)^2008
=-1+0-1
=-2

A and b are mutually opposite numbers
A+b=0
C and d are reciprocal
Cd =1
2Nd power of (x+1)=0
X=-1
X^3+(a+b)^2009-(-cd)^2008
=-1+0-1
=-2