Given that a, b are rational numbers, and satisfy equation 5-√2a=2b+2/3√2-a, find the value of a, b.

Given that a, b are rational numbers, and satisfy equation 5-√2a=2b+2/3√2-a, find the value of a, b.

5-√2A=2b+2/3√2-a
5-√2A=(2b-a)+2/3√2
Because, a, b are rational numbers
Then,5=2b-a and a =-2/3
Solution a =-2/3, b =13/6

5-√2A=2b+2/3√2-a
5-√2A=(2b-a)+2/3√2
Because, a, b are all rational numbers
Then,5=2b-a and a =-2/3
Solution a =-2/3, b =13/6

5-√2A=2b+2/3√2-a
5-√2A=(2b-a)+2/3√2
Because, a, b are all rational numbers
Then,5=2b-a and a =-2/3
Solve a =-2/3, b =13/6

Let abc be a nonzero rational number, then all possible values of a/|a b/|b c/|c| are?

A/|a|=1 or -1
B/|b|=1 or -1
C/|c|=1 or -1
So a/|a|+b/|b|+c/|c|=3 or 1 or -1 or -3

A/|a|=1 or -1
B/|b|=1 or -1
C/|c|=1 or -1
So a/|a |+b/|b |+c/|c|=3 or 1 or -1 or -3