Given the square of |a+1(b-2)=0, find the value of (a+b) to the 2013 power +a to the 2012 power

Square of |a+1(b-2)=0
A+1=0
B-2=0
A=-1
B=2
2013 Power of (a+b)+2012 power of a
2013 Power of =(-1+2)+2012 power of (-1)
=1+1
=2

Square of |a+1(b-2)=0
A+1=0
B-2=0
A=-1
B=2
2013 Power of (a+b)+2012 power of a
=(-1+2)2013+(-1)2012
=1+1
=2

Given that |a-2| and |b+1| are mutually opposite numbers, what is the a-th power of b?

The opposite number adds up to 0
The absolute value is greater than or equal to 0, and the sum is equal to 0. If one is greater than 0, the other is less than 0.
So both equals zero.
So a-2=0, b+1=0
A=2, b=-1
So a power of b =1

The opposite number adds up to 0
The absolute value is greater than or equal to 0, and the sum is equal to 0. If one is greater than 0, the other is less than 0.
So both equal 0.
So a-2=0, b+1=0
A=2, b=-1
So a power of b =1

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