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Given that the first power of 2 is equal to 2, the second power of 2 is equal to 4, and the third power of 2 is equal to 8(1), can you guess the number of the 64th power of 2? (2) Based on the above inferences and in combination with the calculation, estimate the number of bits of (2+1)×(22+1)×(2^4+1)...(2^64+1) Given that the first power of 2 is equal to 2, the second power of 2 is equal to 4, and the third power of 2 is equal to 8(1), can you guess what the number of bits of the 64th power of 2 is? (2) Based on the above inferences and in combination with the calculation, estimate the number of bits of (2+1)×(22+1)×(2^4+1)...(2^64+1)
The digits are 6, followed by 5
The number of digits is 6 and the next digit is 5
2010 Power of (-2)+2011 power of (-2)?
2010 Power of (-2)+2011 power of (-2)
=2^2010-2^2011
=2^2010(1-2)
=-2^2010
(-2)2010+(-2)2011
=2^2010-2^2011
=2^2010(1-2)
=-2^2010
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