(2004 Third power-2*2004 square-2002)/2004 third power +2004 square-2003 The value of?

(2004 Third power-2*2004 square-2002)/2004 third power +2004 square-2003 The value of?

2003 Should be 2005
Make a =2004
2002=A-2
2005= A +1
Original formula =[ a3-2a2-(a-2)]/[ a3+a2-(a+1)]
=(A2-1)(a-2)/[(a2-1)(a+1)]
=(A-2)/(a+1)
=2002/2005

Two-thirds of the 2002 power x (1.5) of the 2003 power ÷(-1) of the 2004 power = Attention is first 2002 power then 2003 power! It's different from what I found online! Two thirds of the 2002 power x (1.5) of the 2003 power ÷(-1) of the 2004 power = Attention is the first 2002 power then 2003 power! It's not the same as what we found online!

(2/3)^2002X (3/2)^2003÷(-1)2004
=[(2/3)^2002X (3/2)^2002x (3/2)]÷1
=3/2
That is to say: first (3/2)^2003=(3/2)^2002x (3/2), then in the use of the reciprocal relationship between the two terms about!
I hope my answer can help you, and wish: hot summer has a cool good mood!